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SELECT COUNT(*) FROM head WHERE age > 56 | CREATE TABLE head (age INTEGER) | How many heads of the departments are older than 56 ? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM head WHERE age > 56 Context: CREATE TABLE head (age INTEGER) [/INST] Based on the provided SQL query and context, your question is: How many heads of the departments are older than 56 ? The answer to your question is: SELECT COUNT(*) FROM head WHERE age > 56. [/s> |
SELECT name, born_state, age FROM head ORDER BY age | CREATE TABLE head (name VARCHAR, born_state VARCHAR, age VARCHAR) | List the name, born state and age of the heads of departments ordered by age. | <s>[INST] Given the following SQL query and context: Query: SELECT name, born_state, age FROM head ORDER BY age Context: CREATE TABLE head (name VARCHAR, born_state VARCHAR, age VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the name, born state and age of the heads of departments ordered by age. The answer to your question is: SELECT name, born_state, age FROM head ORDER BY age. [/s> |
SELECT creation, name, budget_in_billions FROM department | CREATE TABLE department (creation VARCHAR, name VARCHAR, budget_in_billions VARCHAR) | List the creation year, name and budget of each department. | <s>[INST] Given the following SQL query and context: Query: SELECT creation, name, budget_in_billions FROM department Context: CREATE TABLE department (creation VARCHAR, name VARCHAR, budget_in_billions VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the creation year, name and budget of each department. The answer to your question is: SELECT creation, name, budget_in_billions FROM department. [/s> |
SELECT MAX(budget_in_billions), MIN(budget_in_billions) FROM department | CREATE TABLE department (budget_in_billions INTEGER) | What are the maximum and minimum budget of the departments? | <s>[INST] Given the following SQL query and context: Query: SELECT MAX(budget_in_billions), MIN(budget_in_billions) FROM department Context: CREATE TABLE department (budget_in_billions INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the maximum and minimum budget of the departments? The answer to your question is: SELECT MAX(budget_in_billions), MIN(budget_in_billions) FROM department. [/s> |
SELECT AVG(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15 | CREATE TABLE department (num_employees INTEGER, ranking INTEGER) | What is the average number of employees of the departments whose rank is between 10 and 15? | <s>[INST] Given the following SQL query and context: Query: SELECT AVG(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15 Context: CREATE TABLE department (num_employees INTEGER, ranking INTEGER) [/INST] Based on the provided SQL query and context, your question is: What is the average number of employees of the departments whose rank is between 10 and 15? The answer to your question is: SELECT AVG(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15. [/s> |
SELECT name FROM head WHERE born_state <> 'California' | CREATE TABLE head (name VARCHAR, born_state VARCHAR) | What are the names of the heads who are born outside the California state? | <s>[INST] Given the following SQL query and context: Query: SELECT name FROM head WHERE born_state <> 'California' Context: CREATE TABLE head (name VARCHAR, born_state VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the names of the heads who are born outside the California state? The answer to your question is: SELECT name FROM head WHERE born_state <> 'California'. [/s> |
SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama' | CREATE TABLE department (creation VARCHAR, department_id VARCHAR); CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (head_id VARCHAR, born_state VARCHAR) | What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'? | <s>[INST] Given the following SQL query and context: Query: SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama' Context: CREATE TABLE department (creation VARCHAR, department_id VARCHAR); CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (head_id VARCHAR, born_state VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'? The answer to your question is: SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'. [/s> |
SELECT born_state FROM head GROUP BY born_state HAVING COUNT(*) >= 3 | CREATE TABLE head (born_state VARCHAR) | What are the names of the states where at least 3 heads were born? | <s>[INST] Given the following SQL query and context: Query: SELECT born_state FROM head GROUP BY born_state HAVING COUNT(*) >= 3 Context: CREATE TABLE head (born_state VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the names of the states where at least 3 heads were born? The answer to your question is: SELECT born_state FROM head GROUP BY born_state HAVING COUNT(*) >= 3. [/s> |
SELECT creation FROM department GROUP BY creation ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE department (creation VARCHAR) | In which year were most departments established? | <s>[INST] Given the following SQL query and context: Query: SELECT creation FROM department GROUP BY creation ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE department (creation VARCHAR) [/INST] Based on the provided SQL query and context, your question is: In which year were most departments established? The answer to your question is: SELECT creation FROM department GROUP BY creation ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT T1.name, T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes' | CREATE TABLE management (department_id VARCHAR, temporary_acting VARCHAR); CREATE TABLE department (name VARCHAR, num_employees VARCHAR, department_id VARCHAR) | Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.name, T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes' Context: CREATE TABLE management (department_id VARCHAR, temporary_acting VARCHAR); CREATE TABLE department (name VARCHAR, num_employees VARCHAR, department_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'? The answer to your question is: SELECT T1.name, T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'. [/s> |
SELECT COUNT(DISTINCT temporary_acting) FROM management | CREATE TABLE management (temporary_acting VARCHAR) | How many acting statuses are there? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(DISTINCT temporary_acting) FROM management Context: CREATE TABLE management (temporary_acting VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many acting statuses are there? The answer to your question is: SELECT COUNT(DISTINCT temporary_acting) FROM management. [/s> |
SELECT COUNT(*) FROM department WHERE NOT department_id IN (SELECT department_id FROM management) | CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR) | How many departments are led by heads who are not mentioned? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM department WHERE NOT department_id IN (SELECT department_id FROM management) Context: CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many departments are led by heads who are not mentioned? The answer to your question is: SELECT COUNT(*) FROM department WHERE NOT department_id IN (SELECT department_id FROM management). [/s> |
SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes' | CREATE TABLE head (age VARCHAR, head_id VARCHAR); CREATE TABLE management (head_id VARCHAR, temporary_acting VARCHAR) | What are the distinct ages of the heads who are acting? | <s>[INST] Given the following SQL query and context: Query: SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes' Context: CREATE TABLE head (age VARCHAR, head_id VARCHAR); CREATE TABLE management (head_id VARCHAR, temporary_acting VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the distinct ages of the heads who are acting? The answer to your question is: SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'. [/s> |
SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security' | CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (born_state VARCHAR, head_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR) | List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born. | <s>[INST] Given the following SQL query and context: Query: SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security' Context: CREATE TABLE management (department_id VARCHAR, head_id VARCHAR); CREATE TABLE head (born_state VARCHAR, head_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born. The answer to your question is: SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'. [/s> |
SELECT T1.department_id, T1.name, COUNT(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING COUNT(*) > 1 | CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR) | Which department has more than 1 head at a time? List the id, name and the number of heads. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.department_id, T1.name, COUNT(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING COUNT(*) > 1 Context: CREATE TABLE management (department_id VARCHAR); CREATE TABLE department (department_id VARCHAR, name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Which department has more than 1 head at a time? List the id, name and the number of heads. The answer to your question is: SELECT T1.department_id, T1.name, COUNT(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING COUNT(*) > 1. [/s> |
SELECT head_id, name FROM head WHERE name LIKE '%Ha%' | CREATE TABLE head (head_id VARCHAR, name VARCHAR) | Which head's name has the substring 'Ha'? List the id and name. | <s>[INST] Given the following SQL query and context: Query: SELECT head_id, name FROM head WHERE name LIKE '%Ha%' Context: CREATE TABLE head (head_id VARCHAR, name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Which head's name has the substring 'Ha'? List the id and name. The answer to your question is: SELECT head_id, name FROM head WHERE name LIKE '%Ha%'. [/s> |
SELECT COUNT(*) FROM farm | CREATE TABLE farm (Id VARCHAR) | How many farms are there? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM farm Context: CREATE TABLE farm (Id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many farms are there? The answer to your question is: SELECT COUNT(*) FROM farm. [/s> |
SELECT Total_Horses FROM farm ORDER BY Total_Horses | CREATE TABLE farm (Total_Horses VARCHAR) | List the total number of horses on farms in ascending order. | <s>[INST] Given the following SQL query and context: Query: SELECT Total_Horses FROM farm ORDER BY Total_Horses Context: CREATE TABLE farm (Total_Horses VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the total number of horses on farms in ascending order. The answer to your question is: SELECT Total_Horses FROM farm ORDER BY Total_Horses. [/s> |
SELECT Hosts FROM farm_competition WHERE Theme <> 'Aliens' | CREATE TABLE farm_competition (Hosts VARCHAR, Theme VARCHAR) | What are the hosts of competitions whose theme is not "Aliens"? | <s>[INST] Given the following SQL query and context: Query: SELECT Hosts FROM farm_competition WHERE Theme <> 'Aliens' Context: CREATE TABLE farm_competition (Hosts VARCHAR, Theme VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the hosts of competitions whose theme is not "Aliens"? The answer to your question is: SELECT Hosts FROM farm_competition WHERE Theme <> 'Aliens'. [/s> |
SELECT Theme FROM farm_competition ORDER BY YEAR | CREATE TABLE farm_competition (Theme VARCHAR, YEAR VARCHAR) | What are the themes of farm competitions sorted by year in ascending order? | <s>[INST] Given the following SQL query and context: Query: SELECT Theme FROM farm_competition ORDER BY YEAR Context: CREATE TABLE farm_competition (Theme VARCHAR, YEAR VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the themes of farm competitions sorted by year in ascending order? The answer to your question is: SELECT Theme FROM farm_competition ORDER BY YEAR. [/s> |
SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000 | CREATE TABLE farm (Working_Horses INTEGER, Total_Horses INTEGER) | What is the average number of working horses of farms with more than 5000 total number of horses? | <s>[INST] Given the following SQL query and context: Query: SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000 Context: CREATE TABLE farm (Working_Horses INTEGER, Total_Horses INTEGER) [/INST] Based on the provided SQL query and context, your question is: What is the average number of working horses of farms with more than 5000 total number of horses? The answer to your question is: SELECT AVG(Working_Horses) FROM farm WHERE Total_Horses > 5000. [/s> |
SELECT MAX(Cows), MIN(Cows) FROM farm | CREATE TABLE farm (Cows INTEGER) | What are the maximum and minimum number of cows across all farms. | <s>[INST] Given the following SQL query and context: Query: SELECT MAX(Cows), MIN(Cows) FROM farm Context: CREATE TABLE farm (Cows INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the maximum and minimum number of cows across all farms. The answer to your question is: SELECT MAX(Cows), MIN(Cows) FROM farm. [/s> |
SELECT COUNT(DISTINCT Status) FROM city | CREATE TABLE city (Status VARCHAR) | How many different statuses do cities have? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(DISTINCT Status) FROM city Context: CREATE TABLE city (Status VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many different statuses do cities have? The answer to your question is: SELECT COUNT(DISTINCT Status) FROM city. [/s> |
SELECT Official_Name FROM city ORDER BY Population DESC | CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR) | List official names of cities in descending order of population. | <s>[INST] Given the following SQL query and context: Query: SELECT Official_Name FROM city ORDER BY Population DESC Context: CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List official names of cities in descending order of population. The answer to your question is: SELECT Official_Name FROM city ORDER BY Population DESC. [/s> |
SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1 | CREATE TABLE city (Official_Name VARCHAR, Status VARCHAR, Population VARCHAR) | List the official name and status of the city with the largest population. | <s>[INST] Given the following SQL query and context: Query: SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1 Context: CREATE TABLE city (Official_Name VARCHAR, Status VARCHAR, Population VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the official name and status of the city with the largest population. The answer to your question is: SELECT Official_Name, Status FROM city ORDER BY Population DESC LIMIT 1. [/s> |
SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID | CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Year VARCHAR, Host_city_ID VARCHAR) | Show the years and the official names of the host cities of competitions. | <s>[INST] Given the following SQL query and context: Query: SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID Context: CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Year VARCHAR, Host_city_ID VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Show the years and the official names of the host cities of competitions. The answer to your question is: SELECT T2.Year, T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID. [/s> |
SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1 | CREATE TABLE farm_competition (Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR) | Show the official names of the cities that have hosted more than one competition. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1 Context: CREATE TABLE farm_competition (Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Show the official names of the cities that have hosted more than one competition. The answer to your question is: SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1. [/s> |
SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE city (Status VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Host_city_ID VARCHAR) | Show the status of the city that has hosted the greatest number of competitions. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE city (Status VARCHAR, City_ID VARCHAR); CREATE TABLE farm_competition (Host_city_ID VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Show the status of the city that has hosted the greatest number of competitions. The answer to your question is: SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000 | CREATE TABLE city (City_ID VARCHAR, Population INTEGER); CREATE TABLE farm_competition (Theme VARCHAR, Host_city_ID VARCHAR) | Please show the themes of competitions with host cities having populations larger than 1000. | <s>[INST] Given the following SQL query and context: Query: SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000 Context: CREATE TABLE city (City_ID VARCHAR, Population INTEGER); CREATE TABLE farm_competition (Theme VARCHAR, Host_city_ID VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Please show the themes of competitions with host cities having populations larger than 1000. The answer to your question is: SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000. [/s> |
SELECT Status, AVG(Population) FROM city GROUP BY Status | CREATE TABLE city (Status VARCHAR, Population INTEGER) | Please show the different statuses of cities and the average population of cities with each status. | <s>[INST] Given the following SQL query and context: Query: SELECT Status, AVG(Population) FROM city GROUP BY Status Context: CREATE TABLE city (Status VARCHAR, Population INTEGER) [/INST] Based on the provided SQL query and context, your question is: Please show the different statuses of cities and the average population of cities with each status. The answer to your question is: SELECT Status, AVG(Population) FROM city GROUP BY Status. [/s> |
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) | CREATE TABLE city (Status VARCHAR) | Please show the different statuses, ordered by the number of cities that have each. | <s>[INST] Given the following SQL query and context: Query: SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) Context: CREATE TABLE city (Status VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Please show the different statuses, ordered by the number of cities that have each. The answer to your question is: SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*). [/s> |
SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE city (Status VARCHAR) | List the most common type of Status across cities. | <s>[INST] Given the following SQL query and context: Query: SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE city (Status VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the most common type of Status across cities. The answer to your question is: SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition) | CREATE TABLE farm_competition (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR) | List the official names of cities that have not held any competition. | <s>[INST] Given the following SQL query and context: Query: SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition) Context: CREATE TABLE farm_competition (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR); CREATE TABLE city (Official_Name VARCHAR, City_ID VARCHAR, Host_city_ID VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the official names of cities that have not held any competition. The answer to your question is: SELECT Official_Name FROM city WHERE NOT City_ID IN (SELECT Host_city_ID FROM farm_competition). [/s> |
SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500 | CREATE TABLE city (Status VARCHAR, Population INTEGER) | Show the status shared by cities with population bigger than 1500 and smaller than 500. | <s>[INST] Given the following SQL query and context: Query: SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500 Context: CREATE TABLE city (Status VARCHAR, Population INTEGER) [/INST] Based on the provided SQL query and context, your question is: Show the status shared by cities with population bigger than 1500 and smaller than 500. The answer to your question is: SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500. [/s> |
SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500 | CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR) | Find the official names of cities with population bigger than 1500 or smaller than 500. | <s>[INST] Given the following SQL query and context: Query: SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500 Context: CREATE TABLE city (Official_Name VARCHAR, Population VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find the official names of cities with population bigger than 1500 or smaller than 500. The answer to your question is: SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500. [/s> |
SELECT Census_Ranking FROM city WHERE Status <> "Village" | CREATE TABLE city (Census_Ranking VARCHAR, Status VARCHAR) | Show the census ranking of cities whose status are not "Village". | <s>[INST] Given the following SQL query and context: Query: SELECT Census_Ranking FROM city WHERE Status <> "Village" Context: CREATE TABLE city (Census_Ranking VARCHAR, Status VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Show the census ranking of cities whose status are not "Village". The answer to your question is: SELECT Census_Ranking FROM city WHERE Status <> "Village". [/s> |
SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_Id VARCHAR) | which course has most number of registered students? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_Id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: which course has most number of registered students? The answer to your question is: SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1 | CREATE TABLE student_course_registrations (student_id VARCHAR) | what is id of students who registered some courses but the least number of courses in these students? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1 Context: CREATE TABLE student_course_registrations (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: what is id of students who registered some courses but the least number of courses in these students? The answer to your question is: SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY COUNT(*) LIMIT 1. [/s> |
SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id | CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (first_name VARCHAR, last_name VARCHAR, person_id VARCHAR) | what are the first name and last name of all candidates? | <s>[INST] Given the following SQL query and context: Query: SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id Context: CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (first_name VARCHAR, last_name VARCHAR, person_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: what are the first name and last name of all candidates? The answer to your question is: SELECT T2.first_name, T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id. [/s> |
SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance) | CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE students (student_id VARCHAR) | List the id of students who never attends courses? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance) Context: CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE students (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the id of students who never attends courses? The answer to your question is: SELECT student_id FROM students WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance). [/s> |
SELECT student_id FROM student_course_attendance | CREATE TABLE student_course_attendance (student_id VARCHAR) | List the id of students who attended some courses? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM student_course_attendance Context: CREATE TABLE student_course_attendance (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the id of students who attended some courses? The answer to your question is: SELECT student_id FROM student_course_attendance. [/s> |
SELECT T1.student_id, T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id | CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR) | What are the ids of all students for courses and what are the names of those courses? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.student_id, T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id Context: CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the ids of all students for courses and what are the names of those courses? The answer to your question is: SELECT T1.student_id, T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id. [/s> |
SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1 | CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR); CREATE TABLE students (student_details VARCHAR, student_id VARCHAR) | What is detail of the student who most recently registered course? | <s>[INST] Given the following SQL query and context: Query: SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1 Context: CREATE TABLE student_course_registrations (student_id VARCHAR, registration_date VARCHAR); CREATE TABLE students (student_details VARCHAR, student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is detail of the student who most recently registered course? The answer to your question is: SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1. [/s> |
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English" | CREATE TABLE student_course_attendance (course_id VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) | How many students attend course English? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English" Context: CREATE TABLE student_course_attendance (course_id VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many students attend course English? The answer to your question is: SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English". [/s> |
SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171 | CREATE TABLE courses (course_id VARCHAR); CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR) | How many courses do the student whose id is 171 attend? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171 Context: CREATE TABLE courses (course_id VARCHAR); CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many courses do the student whose id is 171 attend? The answer to your question is: SELECT COUNT(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171. [/s> |
SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]" | CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (person_id VARCHAR, email_address VARCHAR) | Find id of the candidate whose email is [email protected]? | <s>[INST] Given the following SQL query and context: Query: SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]" Context: CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (person_id VARCHAR, email_address VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find id of the candidate whose email is [email protected]? The answer to your question is: SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "[email protected]". [/s> |
SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1 | CREATE TABLE candidate_assessments (candidate_id VARCHAR, assessment_date VARCHAR) | Find id of the candidate who most recently accessed the course? | <s>[INST] Given the following SQL query and context: Query: SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1 Context: CREATE TABLE candidate_assessments (candidate_id VARCHAR, assessment_date VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find id of the candidate who most recently accessed the course? The answer to your question is: SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1. [/s> |
SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE students (student_details VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) | What is detail of the student who registered the most number of courses? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE students (student_details VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is detail of the student who registered the most number of courses? The answer to your question is: SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id | CREATE TABLE students (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) | List the id of students who registered some courses and the number of their registered courses? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id Context: CREATE TABLE students (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the id of students who registered some courses and the number of their registered courses? The answer to your question is: SELECT T1.student_id, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id. [/s> |
SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id | CREATE TABLE students (student_id VARCHAR); CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR) | How many registed students do each course have? List course name and the number of their registered students? | <s>[INST] Given the following SQL query and context: Query: SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id Context: CREATE TABLE students (student_id VARCHAR); CREATE TABLE courses (course_name VARCHAR, course_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many registed students do each course have? List course name and the number of their registered students? The answer to your question is: SELECT T3.course_name, COUNT(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id. [/s> |
SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass" | CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR) | Find id of candidates whose assessment code is "Pass"? | <s>[INST] Given the following SQL query and context: Query: SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass" Context: CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find id of candidates whose assessment code is "Pass"? The answer to your question is: SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass". [/s> |
SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail" | CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (cell_mobile_number VARCHAR, person_id VARCHAR); CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR) | Find the cell mobile number of the candidates whose assessment code is "Fail"? | <s>[INST] Given the following SQL query and context: Query: SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail" Context: CREATE TABLE candidates (candidate_id VARCHAR); CREATE TABLE people (cell_mobile_number VARCHAR, person_id VARCHAR); CREATE TABLE candidate_assessments (candidate_id VARCHAR, asessment_outcome_code VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find the cell mobile number of the candidates whose assessment code is "Fail"? The answer to your question is: SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail". [/s> |
SELECT student_id FROM student_course_attendance WHERE course_id = 301 | CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR) | What are the id of students who registered course 301? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM student_course_attendance WHERE course_id = 301 Context: CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the id of students who registered course 301? The answer to your question is: SELECT student_id FROM student_course_attendance WHERE course_id = 301. [/s> |
SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1 | CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR) | What is the id of the student who most recently registered course 301? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1 Context: CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the id of the student who most recently registered course 301? The answer to your question is: SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1. [/s> |
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id | CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR) | Find distinct cities of addresses of people? | <s>[INST] Given the following SQL query and context: Query: SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id Context: CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find distinct cities of addresses of people? The answer to your question is: SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id. [/s> |
SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id | CREATE TABLE students (student_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR, person_id VARCHAR) | Find distinct cities of address of students? | <s>[INST] Given the following SQL query and context: Query: SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id Context: CREATE TABLE students (student_id VARCHAR); CREATE TABLE addresses (city VARCHAR, address_id VARCHAR); CREATE TABLE people_addresses (address_id VARCHAR, person_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find distinct cities of address of students? The answer to your question is: SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id. [/s> |
SELECT course_name FROM courses ORDER BY course_name | CREATE TABLE courses (course_name VARCHAR) | List the names of courses in alphabetical order? | <s>[INST] Given the following SQL query and context: Query: SELECT course_name FROM courses ORDER BY course_name Context: CREATE TABLE courses (course_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the names of courses in alphabetical order? The answer to your question is: SELECT course_name FROM courses ORDER BY course_name. [/s> |
SELECT first_name FROM people ORDER BY first_name | CREATE TABLE people (first_name VARCHAR) | List the first names of people in alphabetical order? | <s>[INST] Given the following SQL query and context: Query: SELECT first_name FROM people ORDER BY first_name Context: CREATE TABLE people (first_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the first names of people in alphabetical order? The answer to your question is: SELECT first_name FROM people ORDER BY first_name. [/s> |
SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance | CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) | What are the id of students who registered courses or attended courses? | <s>[INST] Given the following SQL query and context: Query: SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance Context: CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the id of students who registered courses or attended courses? The answer to your question is: SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance. [/s> |
SELECT course_id FROM student_course_registrations WHERE student_id = 121 UNION SELECT course_id FROM student_course_attendance WHERE student_id = 121 | CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR) | Find the id of courses which are registered or attended by student whose id is 121? | <s>[INST] Given the following SQL query and context: Query: SELECT course_id FROM student_course_registrations WHERE student_id = 121 UNION SELECT course_id FROM student_course_attendance WHERE student_id = 121 Context: CREATE TABLE student_course_attendance (course_id VARCHAR, student_id VARCHAR); CREATE TABLE student_course_registrations (course_id VARCHAR, student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find the id of courses which are registered or attended by student whose id is 121? The answer to your question is: SELECT course_id FROM student_course_registrations WHERE student_id = 121 UNION SELECT course_id FROM student_course_attendance WHERE student_id = 121. [/s> |
SELECT * FROM student_course_registrations WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance) | CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) | What are all info of students who registered courses but not attended courses? | <s>[INST] Given the following SQL query and context: Query: SELECT * FROM student_course_registrations WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance) Context: CREATE TABLE student_course_attendance (student_id VARCHAR); CREATE TABLE student_course_registrations (student_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are all info of students who registered courses but not attended courses? The answer to your question is: SELECT * FROM student_course_registrations WHERE NOT student_id IN (SELECT student_id FROM student_course_attendance). [/s> |
SELECT T2.student_id FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.registration_date | CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR, registration_date VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) | List the id of students who registered course statistics in the order of registration date. | <s>[INST] Given the following SQL query and context: Query: SELECT T2.student_id FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.registration_date Context: CREATE TABLE student_course_registrations (student_id VARCHAR, course_id VARCHAR, registration_date VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the id of students who registered course statistics in the order of registration date. The answer to your question is: SELECT T2.student_id FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.registration_date. [/s> |
SELECT T2.student_id FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.date_of_attendance | CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) | List the id of students who attended statistics courses in the order of attendance date. | <s>[INST] Given the following SQL query and context: Query: SELECT T2.student_id FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.date_of_attendance Context: CREATE TABLE student_course_attendance (student_id VARCHAR, course_id VARCHAR, date_of_attendance VARCHAR); CREATE TABLE courses (course_id VARCHAR, course_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the id of students who attended statistics courses in the order of attendance date. The answer to your question is: SELECT T2.student_id FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "statistics" ORDER BY T2.date_of_attendance. [/s> |
SELECT date FROM weather WHERE max_temperature_f > 85 | CREATE TABLE weather (date VARCHAR, max_temperature_f INTEGER) | Give me the dates when the max temperature was higher than 85. | <s>[INST] Given the following SQL query and context: Query: SELECT date FROM weather WHERE max_temperature_f > 85 Context: CREATE TABLE weather (date VARCHAR, max_temperature_f INTEGER) [/INST] Based on the provided SQL query and context, your question is: Give me the dates when the max temperature was higher than 85. The answer to your question is: SELECT date FROM weather WHERE max_temperature_f > 85. [/s> |
SELECT name FROM station WHERE lat < 37.5 | CREATE TABLE station (name VARCHAR, lat INTEGER) | What are the names of stations that have latitude lower than 37.5? | <s>[INST] Given the following SQL query and context: Query: SELECT name FROM station WHERE lat < 37.5 Context: CREATE TABLE station (name VARCHAR, lat INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the names of stations that have latitude lower than 37.5? The answer to your question is: SELECT name FROM station WHERE lat < 37.5. [/s> |
SELECT city, MAX(lat) FROM station GROUP BY city | CREATE TABLE station (city VARCHAR, lat INTEGER) | For each city, return the highest latitude among its stations. | <s>[INST] Given the following SQL query and context: Query: SELECT city, MAX(lat) FROM station GROUP BY city Context: CREATE TABLE station (city VARCHAR, lat INTEGER) [/INST] Based on the provided SQL query and context, your question is: For each city, return the highest latitude among its stations. The answer to your question is: SELECT city, MAX(lat) FROM station GROUP BY city. [/s> |
SELECT start_station_name, end_station_name FROM trip ORDER BY id LIMIT 3 | CREATE TABLE trip (start_station_name VARCHAR, end_station_name VARCHAR, id VARCHAR) | Give me the start station and end station for the trips with the three oldest id. | <s>[INST] Given the following SQL query and context: Query: SELECT start_station_name, end_station_name FROM trip ORDER BY id LIMIT 3 Context: CREATE TABLE trip (start_station_name VARCHAR, end_station_name VARCHAR, id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Give me the start station and end station for the trips with the three oldest id. The answer to your question is: SELECT start_station_name, end_station_name FROM trip ORDER BY id LIMIT 3. [/s> |
SELECT AVG(lat), AVG(long) FROM station WHERE city = "San Jose" | CREATE TABLE station (lat INTEGER, long INTEGER, city VARCHAR) | What is the average latitude and longitude of stations located in San Jose city? | <s>[INST] Given the following SQL query and context: Query: SELECT AVG(lat), AVG(long) FROM station WHERE city = "San Jose" Context: CREATE TABLE station (lat INTEGER, long INTEGER, city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the average latitude and longitude of stations located in San Jose city? The answer to your question is: SELECT AVG(lat), AVG(long) FROM station WHERE city = "San Jose". [/s> |
SELECT id FROM trip ORDER BY duration LIMIT 1 | CREATE TABLE trip (id VARCHAR, duration VARCHAR) | What is the id of the trip that has the shortest duration? | <s>[INST] Given the following SQL query and context: Query: SELECT id FROM trip ORDER BY duration LIMIT 1 Context: CREATE TABLE trip (id VARCHAR, duration VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the id of the trip that has the shortest duration? The answer to your question is: SELECT id FROM trip ORDER BY duration LIMIT 1. [/s> |
SELECT SUM(duration), MAX(duration) FROM trip WHERE bike_id = 636 | CREATE TABLE trip (duration INTEGER, bike_id VARCHAR) | What is the total and maximum duration of trips with bike id 636? | <s>[INST] Given the following SQL query and context: Query: SELECT SUM(duration), MAX(duration) FROM trip WHERE bike_id = 636 Context: CREATE TABLE trip (duration INTEGER, bike_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the total and maximum duration of trips with bike id 636? The answer to your question is: SELECT SUM(duration), MAX(duration) FROM trip WHERE bike_id = 636. [/s> |
SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code | CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER, date VARCHAR) | For each zip code, return the average mean temperature of August there. | <s>[INST] Given the following SQL query and context: Query: SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code Context: CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER, date VARCHAR) [/INST] Based on the provided SQL query and context, your question is: For each zip code, return the average mean temperature of August there. The answer to your question is: SELECT zip_code, AVG(mean_temperature_f) FROM weather WHERE date LIKE "8/%" GROUP BY zip_code. [/s> |
SELECT COUNT(DISTINCT bike_id) FROM trip | CREATE TABLE trip (bike_id VARCHAR) | From the trip record, find the number of unique bikes. | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(DISTINCT bike_id) FROM trip Context: CREATE TABLE trip (bike_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: From the trip record, find the number of unique bikes. The answer to your question is: SELECT COUNT(DISTINCT bike_id) FROM trip. [/s> |
SELECT COUNT(DISTINCT city) FROM station | CREATE TABLE station (city VARCHAR) | What is the number of distinct cities the stations are located at? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(DISTINCT city) FROM station Context: CREATE TABLE station (city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the number of distinct cities the stations are located at? The answer to your question is: SELECT COUNT(DISTINCT city) FROM station. [/s> |
SELECT COUNT(*) FROM station WHERE city = "Mountain View" | CREATE TABLE station (city VARCHAR) | How many stations does Mountain View city has? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM station WHERE city = "Mountain View" Context: CREATE TABLE station (city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many stations does Mountain View city has? The answer to your question is: SELECT COUNT(*) FROM station WHERE city = "Mountain View". [/s> |
SELECT DISTINCT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available = 7 | CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available VARCHAR) | Return the unique name for stations that have ever had 7 bikes available. | <s>[INST] Given the following SQL query and context: Query: SELECT DISTINCT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available = 7 Context: CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Return the unique name for stations that have ever had 7 bikes available. The answer to your question is: SELECT DISTINCT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available = 7. [/s> |
SELECT start_station_name, start_station_id FROM trip WHERE start_date LIKE "8/%" GROUP BY start_station_name ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE trip (start_station_name VARCHAR, start_station_id VARCHAR, start_date VARCHAR) | Which start station had the most trips starting from August? Give me the name and id of the station. | <s>[INST] Given the following SQL query and context: Query: SELECT start_station_name, start_station_id FROM trip WHERE start_date LIKE "8/%" GROUP BY start_station_name ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE trip (start_station_name VARCHAR, start_station_id VARCHAR, start_date VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Which start station had the most trips starting from August? Give me the name and id of the station. The answer to your question is: SELECT start_station_name, start_station_id FROM trip WHERE start_date LIKE "8/%" GROUP BY start_station_name ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT bike_id FROM trip WHERE zip_code = 94002 GROUP BY bike_id ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE trip (bike_id VARCHAR, zip_code VARCHAR) | Which bike traveled the most often in zip code 94002? | <s>[INST] Given the following SQL query and context: Query: SELECT bike_id FROM trip WHERE zip_code = 94002 GROUP BY bike_id ORDER BY COUNT(*) DESC LIMIT 1 Context: CREATE TABLE trip (bike_id VARCHAR, zip_code VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Which bike traveled the most often in zip code 94002? The answer to your question is: SELECT bike_id FROM trip WHERE zip_code = 94002 GROUP BY bike_id ORDER BY COUNT(*) DESC LIMIT 1. [/s> |
SELECT COUNT(*) FROM weather WHERE mean_humidity > 50 AND mean_visibility_miles > 8 | CREATE TABLE weather (mean_humidity VARCHAR, mean_visibility_miles VARCHAR) | How many days had both mean humidity above 50 and mean visibility above 8? | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM weather WHERE mean_humidity > 50 AND mean_visibility_miles > 8 Context: CREATE TABLE weather (mean_humidity VARCHAR, mean_visibility_miles VARCHAR) [/INST] Based on the provided SQL query and context, your question is: How many days had both mean humidity above 50 and mean visibility above 8? The answer to your question is: SELECT COUNT(*) FROM weather WHERE mean_humidity > 50 AND mean_visibility_miles > 8. [/s> |
SELECT T1.lat, T1.long, T1.city FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id ORDER BY T2.duration LIMIT 1 | CREATE TABLE trip (start_station_id VARCHAR, duration VARCHAR); CREATE TABLE station (lat VARCHAR, long VARCHAR, city VARCHAR, id VARCHAR) | What is the latitude, longitude, city of the station from which the shortest trip started? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.lat, T1.long, T1.city FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id ORDER BY T2.duration LIMIT 1 Context: CREATE TABLE trip (start_station_id VARCHAR, duration VARCHAR); CREATE TABLE station (lat VARCHAR, long VARCHAR, city VARCHAR, id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the latitude, longitude, city of the station from which the shortest trip started? The answer to your question is: SELECT T1.lat, T1.long, T1.city FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id ORDER BY T2.duration LIMIT 1. [/s> |
SELECT id FROM station WHERE city = "San Francisco" INTERSECT SELECT station_id FROM status GROUP BY station_id HAVING AVG(bikes_available) > 10 | CREATE TABLE status (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER) | What are the ids of stations that are located in San Francisco and have average bike availability above 10. | <s>[INST] Given the following SQL query and context: Query: SELECT id FROM station WHERE city = "San Francisco" INTERSECT SELECT station_id FROM status GROUP BY station_id HAVING AVG(bikes_available) > 10 Context: CREATE TABLE status (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, city VARCHAR, bikes_available INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the ids of stations that are located in San Francisco and have average bike availability above 10. The answer to your question is: SELECT id FROM station WHERE city = "San Francisco" INTERSECT SELECT station_id FROM status GROUP BY station_id HAVING AVG(bikes_available) > 10. [/s> |
SELECT T1.name, T1.id FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(T2.bikes_available) > 14 UNION SELECT name, id FROM station WHERE installation_date LIKE "12/%" | CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE station (name VARCHAR, id VARCHAR, installation_date VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER) | What are the names and ids of stations that had more than 14 bikes available on average or were installed in December? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.name, T1.id FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(T2.bikes_available) > 14 UNION SELECT name, id FROM station WHERE installation_date LIKE "12/%" Context: CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE station (name VARCHAR, id VARCHAR, installation_date VARCHAR); CREATE TABLE status (station_id VARCHAR, bikes_available INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the names and ids of stations that had more than 14 bikes available on average or were installed in December? The answer to your question is: SELECT T1.name, T1.id FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(T2.bikes_available) > 14 UNION SELECT name, id FROM station WHERE installation_date LIKE "12/%". [/s> |
SELECT cloud_cover FROM weather WHERE zip_code = 94107 GROUP BY cloud_cover ORDER BY COUNT(*) DESC LIMIT 3 | CREATE TABLE weather (cloud_cover VARCHAR, zip_code VARCHAR) | What is the 3 most common cloud cover rates in the region of zip code 94107? | <s>[INST] Given the following SQL query and context: Query: SELECT cloud_cover FROM weather WHERE zip_code = 94107 GROUP BY cloud_cover ORDER BY COUNT(*) DESC LIMIT 3 Context: CREATE TABLE weather (cloud_cover VARCHAR, zip_code VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the 3 most common cloud cover rates in the region of zip code 94107? The answer to your question is: SELECT cloud_cover FROM weather WHERE zip_code = 94107 GROUP BY cloud_cover ORDER BY COUNT(*) DESC LIMIT 3. [/s> |
SELECT zip_code FROM weather GROUP BY zip_code ORDER BY AVG(mean_sea_level_pressure_inches) LIMIT 1 | CREATE TABLE weather (zip_code VARCHAR, mean_sea_level_pressure_inches INTEGER) | What is the zip code in which the average mean sea level pressure is the lowest? | <s>[INST] Given the following SQL query and context: Query: SELECT zip_code FROM weather GROUP BY zip_code ORDER BY AVG(mean_sea_level_pressure_inches) LIMIT 1 Context: CREATE TABLE weather (zip_code VARCHAR, mean_sea_level_pressure_inches INTEGER) [/INST] Based on the provided SQL query and context, your question is: What is the zip code in which the average mean sea level pressure is the lowest? The answer to your question is: SELECT zip_code FROM weather GROUP BY zip_code ORDER BY AVG(mean_sea_level_pressure_inches) LIMIT 1. [/s> |
SELECT AVG(bikes_available) FROM status WHERE NOT station_id IN (SELECT id FROM station WHERE city = "Palo Alto") | CREATE TABLE status (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR); CREATE TABLE station (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR) | What is the average bike availability in stations that are not located in Palo Alto? | <s>[INST] Given the following SQL query and context: Query: SELECT AVG(bikes_available) FROM status WHERE NOT station_id IN (SELECT id FROM station WHERE city = "Palo Alto") Context: CREATE TABLE status (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR); CREATE TABLE station (bikes_available INTEGER, station_id VARCHAR, id VARCHAR, city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What is the average bike availability in stations that are not located in Palo Alto? The answer to your question is: SELECT AVG(bikes_available) FROM status WHERE NOT station_id IN (SELECT id FROM station WHERE city = "Palo Alto"). [/s> |
SELECT AVG(long) FROM station WHERE NOT id IN (SELECT station_id FROM status GROUP BY station_id HAVING MAX(bikes_available) > 10) | CREATE TABLE station (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER); CREATE TABLE status (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER) | What is the average longitude of stations that never had bike availability more than 10? | <s>[INST] Given the following SQL query and context: Query: SELECT AVG(long) FROM station WHERE NOT id IN (SELECT station_id FROM status GROUP BY station_id HAVING MAX(bikes_available) > 10) Context: CREATE TABLE station (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER); CREATE TABLE status (long INTEGER, id VARCHAR, station_id VARCHAR, bikes_available INTEGER) [/INST] Based on the provided SQL query and context, your question is: What is the average longitude of stations that never had bike availability more than 10? The answer to your question is: SELECT AVG(long) FROM station WHERE NOT id IN (SELECT station_id FROM status GROUP BY station_id HAVING MAX(bikes_available) > 10). [/s> |
SELECT date, zip_code FROM weather WHERE max_temperature_f >= 80 | CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, max_temperature_f VARCHAR) | When and in what zip code did max temperature reach 80? | <s>[INST] Given the following SQL query and context: Query: SELECT date, zip_code FROM weather WHERE max_temperature_f >= 80 Context: CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, max_temperature_f VARCHAR) [/INST] Based on the provided SQL query and context, your question is: When and in what zip code did max temperature reach 80? The answer to your question is: SELECT date, zip_code FROM weather WHERE max_temperature_f >= 80. [/s> |
SELECT T1.id FROM trip AS T1 JOIN weather AS T2 ON T1.zip_code = T2.zip_code GROUP BY T2.zip_code HAVING AVG(T2.mean_temperature_f) > 60 | CREATE TABLE trip (id VARCHAR, zip_code VARCHAR); CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER) | Give me ids for all the trip that took place in a zip code area with average mean temperature above 60. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.id FROM trip AS T1 JOIN weather AS T2 ON T1.zip_code = T2.zip_code GROUP BY T2.zip_code HAVING AVG(T2.mean_temperature_f) > 60 Context: CREATE TABLE trip (id VARCHAR, zip_code VARCHAR); CREATE TABLE weather (zip_code VARCHAR, mean_temperature_f INTEGER) [/INST] Based on the provided SQL query and context, your question is: Give me ids for all the trip that took place in a zip code area with average mean temperature above 60. The answer to your question is: SELECT T1.id FROM trip AS T1 JOIN weather AS T2 ON T1.zip_code = T2.zip_code GROUP BY T2.zip_code HAVING AVG(T2.mean_temperature_f) > 60. [/s> |
SELECT zip_code, COUNT(*) FROM weather WHERE max_wind_Speed_mph >= 25 GROUP BY zip_code | CREATE TABLE weather (zip_code VARCHAR, max_wind_Speed_mph VARCHAR) | For each zip code, return how many times max wind speed reached 25? | <s>[INST] Given the following SQL query and context: Query: SELECT zip_code, COUNT(*) FROM weather WHERE max_wind_Speed_mph >= 25 GROUP BY zip_code Context: CREATE TABLE weather (zip_code VARCHAR, max_wind_Speed_mph VARCHAR) [/INST] Based on the provided SQL query and context, your question is: For each zip code, return how many times max wind speed reached 25? The answer to your question is: SELECT zip_code, COUNT(*) FROM weather WHERE max_wind_Speed_mph >= 25 GROUP BY zip_code. [/s> |
SELECT date, zip_code FROM weather WHERE min_dew_point_f < (SELECT MIN(min_dew_point_f) FROM weather WHERE zip_code = 94107) | CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, min_dew_point_f INTEGER) | On which day and in which zip code was the min dew point lower than any day in zip code 94107? | <s>[INST] Given the following SQL query and context: Query: SELECT date, zip_code FROM weather WHERE min_dew_point_f < (SELECT MIN(min_dew_point_f) FROM weather WHERE zip_code = 94107) Context: CREATE TABLE weather (date VARCHAR, zip_code VARCHAR, min_dew_point_f INTEGER) [/INST] Based on the provided SQL query and context, your question is: On which day and in which zip code was the min dew point lower than any day in zip code 94107? The answer to your question is: SELECT date, zip_code FROM weather WHERE min_dew_point_f < (SELECT MIN(min_dew_point_f) FROM weather WHERE zip_code = 94107). [/s> |
SELECT T1.id, T2.installation_date FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id | CREATE TABLE station (installation_date VARCHAR, id VARCHAR); CREATE TABLE trip (id VARCHAR, end_station_id VARCHAR) | For each trip, return its ending station's installation date. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.id, T2.installation_date FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id Context: CREATE TABLE station (installation_date VARCHAR, id VARCHAR); CREATE TABLE trip (id VARCHAR, end_station_id VARCHAR) [/INST] Based on the provided SQL query and context, your question is: For each trip, return its ending station's installation date. The answer to your question is: SELECT T1.id, T2.installation_date FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id. [/s> |
SELECT T1.id FROM trip AS T1 JOIN station AS T2 ON T1.start_station_id = T2.id ORDER BY T2.dock_count DESC LIMIT 1 | CREATE TABLE trip (id VARCHAR, start_station_id VARCHAR); CREATE TABLE station (id VARCHAR, dock_count VARCHAR) | Which trip started from the station with the largest dock count? Give me the trip id. | <s>[INST] Given the following SQL query and context: Query: SELECT T1.id FROM trip AS T1 JOIN station AS T2 ON T1.start_station_id = T2.id ORDER BY T2.dock_count DESC LIMIT 1 Context: CREATE TABLE trip (id VARCHAR, start_station_id VARCHAR); CREATE TABLE station (id VARCHAR, dock_count VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Which trip started from the station with the largest dock count? Give me the trip id. The answer to your question is: SELECT T1.id FROM trip AS T1 JOIN station AS T2 ON T1.start_station_id = T2.id ORDER BY T2.dock_count DESC LIMIT 1. [/s> |
SELECT COUNT(*) FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id WHERE T2.city <> "San Francisco" | CREATE TABLE trip (end_station_id VARCHAR); CREATE TABLE station (id VARCHAR, city VARCHAR) | Count the number of trips that did not end in San Francisco city. | <s>[INST] Given the following SQL query and context: Query: SELECT COUNT(*) FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id WHERE T2.city <> "San Francisco" Context: CREATE TABLE trip (end_station_id VARCHAR); CREATE TABLE station (id VARCHAR, city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Count the number of trips that did not end in San Francisco city. The answer to your question is: SELECT COUNT(*) FROM trip AS T1 JOIN station AS T2 ON T1.end_station_id = T2.id WHERE T2.city <> "San Francisco". [/s> |
SELECT date FROM weather WHERE zip_code = 94107 AND EVENTS <> "Fog" AND EVENTS <> "Rain" | CREATE TABLE weather (date VARCHAR, EVENTS VARCHAR, zip_code VARCHAR) | In zip code 94107, on which day neither Fog nor Rain was not observed? | <s>[INST] Given the following SQL query and context: Query: SELECT date FROM weather WHERE zip_code = 94107 AND EVENTS <> "Fog" AND EVENTS <> "Rain" Context: CREATE TABLE weather (date VARCHAR, EVENTS VARCHAR, zip_code VARCHAR) [/INST] Based on the provided SQL query and context, your question is: In zip code 94107, on which day neither Fog nor Rain was not observed? The answer to your question is: SELECT date FROM weather WHERE zip_code = 94107 AND EVENTS <> "Fog" AND EVENTS <> "Rain". [/s> |
SELECT id FROM station WHERE lat > 37.4 EXCEPT SELECT station_id FROM status GROUP BY station_id HAVING MIN(bikes_available) < 7 | CREATE TABLE status (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER) | What are the ids of stations that have latitude above 37.4 and never had bike availability below 7? | <s>[INST] Given the following SQL query and context: Query: SELECT id FROM station WHERE lat > 37.4 EXCEPT SELECT station_id FROM status GROUP BY station_id HAVING MIN(bikes_available) < 7 Context: CREATE TABLE status (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER); CREATE TABLE station (id VARCHAR, station_id VARCHAR, lat INTEGER, bikes_available INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are the ids of stations that have latitude above 37.4 and never had bike availability below 7? The answer to your question is: SELECT id FROM station WHERE lat > 37.4 EXCEPT SELECT station_id FROM status GROUP BY station_id HAVING MIN(bikes_available) < 7. [/s> |
SELECT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(bikes_available) > 10 EXCEPT SELECT name FROM station WHERE city = "San Jose" | CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR); CREATE TABLE station (name VARCHAR, city VARCHAR, bikes_available INTEGER) | What are names of stations that have average bike availability above 10 and are not located in San Jose city? | <s>[INST] Given the following SQL query and context: Query: SELECT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(bikes_available) > 10 EXCEPT SELECT name FROM station WHERE city = "San Jose" Context: CREATE TABLE station (name VARCHAR, id VARCHAR); CREATE TABLE status (station_id VARCHAR); CREATE TABLE station (name VARCHAR, city VARCHAR, bikes_available INTEGER) [/INST] Based on the provided SQL query and context, your question is: What are names of stations that have average bike availability above 10 and are not located in San Jose city? The answer to your question is: SELECT T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id GROUP BY T2.station_id HAVING AVG(bikes_available) > 10 EXCEPT SELECT name FROM station WHERE city = "San Jose". [/s> |
SELECT name, lat, city FROM station ORDER BY lat LIMIT 1 | CREATE TABLE station (name VARCHAR, lat VARCHAR, city VARCHAR) | What are the name, latitude, and city of the station with the lowest latitude? | <s>[INST] Given the following SQL query and context: Query: SELECT name, lat, city FROM station ORDER BY lat LIMIT 1 Context: CREATE TABLE station (name VARCHAR, lat VARCHAR, city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the name, latitude, and city of the station with the lowest latitude? The answer to your question is: SELECT name, lat, city FROM station ORDER BY lat LIMIT 1. [/s> |
SELECT date, mean_temperature_f, mean_humidity FROM weather ORDER BY max_gust_speed_mph DESC LIMIT 3 | CREATE TABLE weather (date VARCHAR, mean_temperature_f VARCHAR, mean_humidity VARCHAR, max_gust_speed_mph VARCHAR) | What are the date, mean temperature and mean humidity for the top 3 days with the largest max gust speeds? | <s>[INST] Given the following SQL query and context: Query: SELECT date, mean_temperature_f, mean_humidity FROM weather ORDER BY max_gust_speed_mph DESC LIMIT 3 Context: CREATE TABLE weather (date VARCHAR, mean_temperature_f VARCHAR, mean_humidity VARCHAR, max_gust_speed_mph VARCHAR) [/INST] Based on the provided SQL query and context, your question is: What are the date, mean temperature and mean humidity for the top 3 days with the largest max gust speeds? The answer to your question is: SELECT date, mean_temperature_f, mean_humidity FROM weather ORDER BY max_gust_speed_mph DESC LIMIT 3. [/s> |
SELECT city, COUNT(*) FROM station GROUP BY city HAVING COUNT(*) >= 15 | CREATE TABLE station (city VARCHAR) | List the name and the number of stations for all the cities that have at least 15 stations. | <s>[INST] Given the following SQL query and context: Query: SELECT city, COUNT(*) FROM station GROUP BY city HAVING COUNT(*) >= 15 Context: CREATE TABLE station (city VARCHAR) [/INST] Based on the provided SQL query and context, your question is: List the name and the number of stations for all the cities that have at least 15 stations. The answer to your question is: SELECT city, COUNT(*) FROM station GROUP BY city HAVING COUNT(*) >= 15. [/s> |
SELECT start_station_id, start_station_name FROM trip GROUP BY start_station_name HAVING COUNT(*) >= 200 | CREATE TABLE trip (start_station_id VARCHAR, start_station_name VARCHAR) | Find the ids and names of stations from which at least 200 trips started. | <s>[INST] Given the following SQL query and context: Query: SELECT start_station_id, start_station_name FROM trip GROUP BY start_station_name HAVING COUNT(*) >= 200 Context: CREATE TABLE trip (start_station_id VARCHAR, start_station_name VARCHAR) [/INST] Based on the provided SQL query and context, your question is: Find the ids and names of stations from which at least 200 trips started. The answer to your question is: SELECT start_station_id, start_station_name FROM trip GROUP BY start_station_name HAVING COUNT(*) >= 200. [/s> |
SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_visibility_miles) < 10 | CREATE TABLE weather (zip_code VARCHAR, mean_visibility_miles INTEGER) | Find the zip code in which the average mean visibility is lower than 10. | <s>[INST] Given the following SQL query and context: Query: SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_visibility_miles) < 10 Context: CREATE TABLE weather (zip_code VARCHAR, mean_visibility_miles INTEGER) [/INST] Based on the provided SQL query and context, your question is: Find the zip code in which the average mean visibility is lower than 10. The answer to your question is: SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_visibility_miles) < 10. [/s> |
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This is dataset contain (78k samples) of the excellent b-mc2/sql-create-context and changed to derekiya/sql-create-context-llama2-78k dataset, processed to match Llama 2's prompt format as described in this article.
Useful if you don't want to reformat it by yourself (e.g., using a script). It was designed for this article about fine-tuning a Llama 2 (chat)
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