Spaces:
Running
on
Zero
Running
on
Zero
# Copyright (c) 2023 Amphion. | |
# | |
# This source code is licensed under the MIT license found in the | |
# LICENSE file in the root directory of this source tree. | |
# This source file is copied from https://github.com/facebookresearch/encodec | |
# Copyright (c) Meta Platforms, Inc. and affiliates. | |
# All rights reserved. | |
# | |
# This source code is licensed under the license found in the | |
# LICENSE file in the root directory of this source tree. | |
"""Arithmetic coder.""" | |
import io | |
import math | |
import random | |
import typing as tp | |
import torch | |
from ..binary import BitPacker, BitUnpacker | |
def build_stable_quantized_cdf( | |
pdf: torch.Tensor, | |
total_range_bits: int, | |
roundoff: float = 1e-8, | |
min_range: int = 2, | |
check: bool = True, | |
) -> torch.Tensor: | |
"""Turn the given PDF into a quantized CDF that splits | |
[0, 2 ** self.total_range_bits - 1] into chunks of size roughly proportional | |
to the PDF. | |
Args: | |
pdf (torch.Tensor): probability distribution, shape should be `[N]`. | |
total_range_bits (int): see `ArithmeticCoder`, the typical range we expect | |
during the coding process is `[0, 2 ** total_range_bits - 1]`. | |
roundoff (float): will round the pdf up to that level to remove difference coming | |
from e.g. evaluating the Language Model on different architectures. | |
min_range (int): minimum range width. Should always be at least 2 for numerical | |
stability. Use this to avoid pathological behavior is a value | |
that is expected to be rare actually happens in real life. | |
check (bool): if True, checks that nothing bad happened, can be deactivated for speed. | |
""" | |
pdf = pdf.detach() | |
if roundoff: | |
pdf = (pdf / roundoff).floor() * roundoff | |
# interpolate with uniform distribution to achieve desired minimum probability. | |
total_range = 2**total_range_bits | |
cardinality = len(pdf) | |
alpha = min_range * cardinality / total_range | |
assert alpha <= 1, "you must reduce min_range" | |
ranges = (((1 - alpha) * total_range) * pdf).floor().long() | |
ranges += min_range | |
quantized_cdf = torch.cumsum(ranges, dim=-1) | |
if min_range < 2: | |
raise ValueError("min_range must be at least 2.") | |
if check: | |
assert quantized_cdf[-1] <= 2**total_range_bits, quantized_cdf[-1] | |
if ( | |
(quantized_cdf[1:] - quantized_cdf[:-1]) < min_range | |
).any() or quantized_cdf[0] < min_range: | |
raise ValueError("You must increase your total_range_bits.") | |
return quantized_cdf | |
class ArithmeticCoder: | |
"""ArithmeticCoder, | |
Let us take a distribution `p` over `N` symbols, and assume we have a stream | |
of random variables `s_t` sampled from `p`. Let us assume that we have a budget | |
of `B` bits that we can afford to write on device. There are `2**B` possible numbers, | |
corresponding to the range `[0, 2 ** B - 1]`. We can map each of those number to a single | |
sequence `(s_t)` by doing the following: | |
1) Initialize the current range to` [0 ** 2 B - 1]`. | |
2) For each time step t, split the current range into contiguous chunks, | |
one for each possible outcome, with size roughly proportional to `p`. | |
For instance, if `p = [0.75, 0.25]`, and the range is `[0, 3]`, the chunks | |
would be `{[0, 2], [3, 3]}`. | |
3) Select the chunk corresponding to `s_t`, and replace the current range with this. | |
4) When done encoding all the values, just select any value remaining in the range. | |
You will notice that this procedure can fail: for instance if at any point in time | |
the range is smaller than `N`, then we can no longer assign a non-empty chunk to each | |
possible outcome. Intuitively, the more likely a value is, the less the range width | |
will reduce, and the longer we can go on encoding values. This makes sense: for any efficient | |
coding scheme, likely outcomes would take less bits, and more of them can be coded | |
with a fixed budget. | |
In practice, we do not know `B` ahead of time, but we have a way to inject new bits | |
when the current range decreases below a given limit (given by `total_range_bits`), without | |
having to redo all the computations. If we encode mostly likely values, we will seldom | |
need to inject new bits, but a single rare value can deplete our stock of entropy! | |
In this explanation, we assumed that the distribution `p` was constant. In fact, the present | |
code works for any sequence `(p_t)` possibly different for each timestep. | |
We also assume that `s_t ~ p_t`, but that doesn't need to be true, although the smaller | |
the KL between the true distribution and `p_t`, the most efficient the coding will be. | |
Args: | |
fo (IO[bytes]): file-like object to which the bytes will be written to. | |
total_range_bits (int): the range `M` described above is `2 ** total_range_bits. | |
Any time the current range width fall under this limit, new bits will | |
be injected to rescale the initial range. | |
""" | |
def __init__(self, fo: tp.IO[bytes], total_range_bits: int = 24): | |
assert total_range_bits <= 30 | |
self.total_range_bits = total_range_bits | |
self.packer = BitPacker(bits=1, fo=fo) # we push single bits at a time. | |
self.low: int = 0 | |
self.high: int = 0 | |
self.max_bit: int = -1 | |
self._dbg: tp.List[tp.Any] = [] | |
self._dbg2: tp.List[tp.Any] = [] | |
def delta(self) -> int: | |
"""Return the current range width.""" | |
return self.high - self.low + 1 | |
def _flush_common_prefix(self): | |
# If self.low and self.high start with the sames bits, | |
# those won't change anymore as we always just increase the range | |
# by powers of 2, and we can flush them out to the bit stream. | |
assert self.high >= self.low, (self.low, self.high) | |
assert self.high < 2 ** (self.max_bit + 1) | |
while self.max_bit >= 0: | |
b1 = self.low >> self.max_bit | |
b2 = self.high >> self.max_bit | |
if b1 == b2: | |
self.low -= b1 << self.max_bit | |
self.high -= b1 << self.max_bit | |
assert self.high >= self.low, (self.high, self.low, self.max_bit) | |
assert self.low >= 0 | |
self.max_bit -= 1 | |
self.packer.push(b1) | |
else: | |
break | |
def push(self, symbol: int, quantized_cdf: torch.Tensor): | |
"""Push the given symbol on the stream, flushing out bits | |
if possible. | |
Args: | |
symbol (int): symbol to encode with the AC. | |
quantized_cdf (torch.Tensor): use `build_stable_quantized_cdf` | |
to build this from your pdf estimate. | |
""" | |
while self.delta < 2**self.total_range_bits: | |
self.low *= 2 | |
self.high = self.high * 2 + 1 | |
self.max_bit += 1 | |
range_low = 0 if symbol == 0 else quantized_cdf[symbol - 1].item() | |
range_high = quantized_cdf[symbol].item() - 1 | |
effective_low = int( | |
math.ceil(range_low * (self.delta / (2**self.total_range_bits))) | |
) | |
effective_high = int( | |
math.floor(range_high * (self.delta / (2**self.total_range_bits))) | |
) | |
assert self.low <= self.high | |
self.high = self.low + effective_high | |
self.low = self.low + effective_low | |
assert self.low <= self.high, ( | |
effective_low, | |
effective_high, | |
range_low, | |
range_high, | |
) | |
self._dbg.append((self.low, self.high)) | |
self._dbg2.append((self.low, self.high)) | |
outs = self._flush_common_prefix() | |
assert self.low <= self.high | |
assert self.max_bit >= -1 | |
assert self.max_bit <= 61, self.max_bit | |
return outs | |
def flush(self): | |
"""Flush the remaining information to the stream.""" | |
while self.max_bit >= 0: | |
b1 = (self.low >> self.max_bit) & 1 | |
self.packer.push(b1) | |
self.max_bit -= 1 | |
self.packer.flush() | |
class ArithmeticDecoder: | |
"""ArithmeticDecoder, see `ArithmeticCoder` for a detailed explanation. | |
Note that this must be called with **exactly** the same parameters and sequence | |
of quantized cdf as the arithmetic encoder or the wrong values will be decoded. | |
If the AC encoder current range is [L, H], with `L` and `H` having the some common | |
prefix (i.e. the same most significant bits), then this prefix will be flushed to the stream. | |
For instances, having read 3 bits `b1 b2 b3`, we know that `[L, H]` is contained inside | |
`[b1 b2 b3 0 ... 0 b1 b3 b3 1 ... 1]`. Now this specific sub-range can only be obtained | |
for a specific sequence of symbols and a binary-search allows us to decode those symbols. | |
At some point, the prefix `b1 b2 b3` will no longer be sufficient to decode new symbols, | |
and we will need to read new bits from the stream and repeat the process. | |
""" | |
def __init__(self, fo: tp.IO[bytes], total_range_bits: int = 24): | |
self.total_range_bits = total_range_bits | |
self.low: int = 0 | |
self.high: int = 0 | |
self.current: int = 0 | |
self.max_bit: int = -1 | |
self.unpacker = BitUnpacker(bits=1, fo=fo) # we pull single bits at a time. | |
# Following is for debugging | |
self._dbg: tp.List[tp.Any] = [] | |
self._dbg2: tp.List[tp.Any] = [] | |
self._last: tp.Any = None | |
def delta(self) -> int: | |
return self.high - self.low + 1 | |
def _flush_common_prefix(self): | |
# Given the current range [L, H], if both have a common prefix, | |
# we know we can remove it from our representation to avoid handling large numbers. | |
while self.max_bit >= 0: | |
b1 = self.low >> self.max_bit | |
b2 = self.high >> self.max_bit | |
if b1 == b2: | |
self.low -= b1 << self.max_bit | |
self.high -= b1 << self.max_bit | |
self.current -= b1 << self.max_bit | |
assert self.high >= self.low | |
assert self.low >= 0 | |
self.max_bit -= 1 | |
else: | |
break | |
def pull(self, quantized_cdf: torch.Tensor) -> tp.Optional[int]: | |
"""Pull a symbol, reading as many bits from the stream as required. | |
This returns `None` when the stream has been exhausted. | |
Args: | |
quantized_cdf (torch.Tensor): use `build_stable_quantized_cdf` | |
to build this from your pdf estimate. This must be **exatly** | |
the same cdf as the one used at encoding time. | |
""" | |
while self.delta < 2**self.total_range_bits: | |
bit = self.unpacker.pull() | |
if bit is None: | |
return None | |
self.low *= 2 | |
self.high = self.high * 2 + 1 | |
self.current = self.current * 2 + bit | |
self.max_bit += 1 | |
def bin_search(low_idx: int, high_idx: int): | |
# Binary search is not just for coding interviews :) | |
if high_idx < low_idx: | |
raise RuntimeError("Binary search failed") | |
mid = (low_idx + high_idx) // 2 | |
range_low = quantized_cdf[mid - 1].item() if mid > 0 else 0 | |
range_high = quantized_cdf[mid].item() - 1 | |
effective_low = int( | |
math.ceil(range_low * (self.delta / (2**self.total_range_bits))) | |
) | |
effective_high = int( | |
math.floor(range_high * (self.delta / (2**self.total_range_bits))) | |
) | |
low = effective_low + self.low | |
high = effective_high + self.low | |
if self.current >= low: | |
if self.current <= high: | |
return (mid, low, high, self.current) | |
else: | |
return bin_search(mid + 1, high_idx) | |
else: | |
return bin_search(low_idx, mid - 1) | |
self._last = (self.low, self.high, self.current, self.max_bit) | |
sym, self.low, self.high, self.current = bin_search(0, len(quantized_cdf) - 1) | |
self._dbg.append((self.low, self.high, self.current)) | |
self._flush_common_prefix() | |
self._dbg2.append((self.low, self.high, self.current)) | |
return sym | |
def test(): | |
torch.manual_seed(1234) | |
random.seed(1234) | |
for _ in range(4): | |
pdfs = [] | |
cardinality = random.randrange(4000) | |
steps = random.randrange(100, 500) | |
fo = io.BytesIO() | |
encoder = ArithmeticCoder(fo) | |
symbols = [] | |
for step in range(steps): | |
pdf = torch.softmax(torch.randn(cardinality), dim=0) | |
pdfs.append(pdf) | |
q_cdf = build_stable_quantized_cdf(pdf, encoder.total_range_bits) | |
symbol = torch.multinomial(pdf, 1).item() | |
symbols.append(symbol) | |
encoder.push(symbol, q_cdf) | |
encoder.flush() | |
fo.seek(0) | |
decoder = ArithmeticDecoder(fo) | |
for idx, (pdf, symbol) in enumerate(zip(pdfs, symbols)): | |
q_cdf = build_stable_quantized_cdf(pdf, encoder.total_range_bits) | |
decoded_symbol = decoder.pull(q_cdf) | |
assert decoded_symbol == symbol, idx | |
assert decoder.pull(torch.zeros(1)) is None | |
if __name__ == "__main__": | |
test() | |