solution
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difficulty
int64
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2 values
#include <bits/stdc++.h> using namespace std; const int mod = 1e9 + 7, SZ = 1e5 + 5; int dx[4] = {-1, 0, 0, 1}; int dy[4] = {0, -1, 1, 0}; int dxx[8] = {0, 1, 1, 1, 0, -1, -1, -1}; int dyy[8] = {1, 1, 0, -1, -1, -1, 0, 1}; int main() { int i, j, fl = 0; int a, b, c, d, m, n, tmp; cin >> a >> b >> c >> d; tmp = b - a + c - d; for (i = 1; i <= 198; i++) { for (j = 1; j <= 198; j++) { if ((j * c - i * a) == tmp) { fl = 1; break; } } if (fl) break; } if (fl) cout << (d + (j - 1) * c) << endl; else cout << "-1\n"; return 0; }
7
CPP
from sys import maxsize, stdout, stdin, stderr # mod = int(1e9 + 7) #import re # can use multiple splits tup = lambda: map(int, stdin.readline().split()) I = lambda: int(stdin.readline()) lint = lambda: [int(x) for x in stdin.readline().split()] S = lambda: stdin.readline().replace('\n', '').strip() #def grid(r, c): return [lint() for i in range(r)] def debug(*args, c=6): print('\033[3{}m'.format(c), *args, '\033[0m', file=stderr) stpr = lambda x : stdout.write(f'{x}' + '\n') star = lambda x : print(' '.join(map(str , x))) from collections import defaultdict,Counter from math import gcd from bisect import bisect_left from math import floor,ceil a , b = tup() c , d = tup() for i in range(1,101): f1 = b + (i-1)*a for j in range(1,101): f2 = d + (j-1)*c #print(f1,f2, i, j) if f2==f1: print(f2) exit() print("-1") # n = I() # ls = lint() # odp = maxsize # odn = maxsize # #print(odp , odn) # s = 0 # for i in ls: # if i > 0: # s+=i # if i%2: # odp = min(odp , i) # else: # if i%2: # odn = min(odn , -i) # #print(s,odp , odn,s - min(odp,odn) ) # if s%2: # print(s) # else: # print(s - min(odp , odn)) #if sum is even you subtract 1 odd value (1 min odd value)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); long long int n, i, j; long long int a1, b1, c1, d1; map<long long int, long long int> ma; cin >> a1 >> b1; cin >> c1 >> d1; for (i = 0; i < 1000006; i++) { ma[b1 + i * a1] = 1; } for (i = 0; i < 1000006; i++) { if (ma[d1 + i * c1] == 1) { cout << d1 + i * c1; return 0; } } cout << -1; return 0; }
7
CPP
a,b=[int(i) for i in input().split()] c,d=[int(i) for i in input().split()] for i in range(0,10000): if b+a*i>=d and (b+a*i-d)%c==0: print(b+a*i) exit(0) print(-1)
7
PYTHON3
import sys,math,io,os,time,itertools,collections mod=10**9+7 sys.setrecursionlimit(10000) i=sys.stdin.readline p=sys.stdout.write #use sys.stdout.write() (remember to convert to str b4 and concatenate "\n") global start,end #binary search def isin(l,x): left=0 right=len(l)-1 if x<l[0]: return -1 while left<=right: mid=left + (right -left)//2 if l[mid]==x: return mid elif l[mid]<x: ans=mid left=mid+1 else: right=mid-1 return ans #is palindrome or not def ispal(l): n=len(l) for i in range(n//2+1): if l[i]!=l[n-i-1]: return False return True #coordinate compression def ccarray(l): d={l[k]:k for k in range(len(l))} m=sorted(d) return [d[m[k]] for k in range(len(l))] #checks if prime or not def is_prime(n): if n<=3: return n>1 if n%2==0 or n%3==0: return False k=5 while k**2<=n: if n%k==0 or n%(k+2)==0: return False k+=6 return True #sieve of eratosthenes def sieve(n): prime=[True for k in range(n+1)] p=2 while p*p<=n: if prime[p]==True: for k in range(p*p,n+1,p): prime[k]=False p+=1 def main(): a,b=[int(k) for k in i().split()] c,d=[int(k) for k in i().split()] ans=0 if b>=d: for k in range(c): temp=b-d+k*a if temp%c==0: p(str(b+a*k)+"\n") break else: p("-1\n") else: for k in range(a): temp=d-b+k*c if temp%a==0: p(str(d+c*k)+"\n") break else: p("-1\n") t=1 #t=int(i()) start=time.perf_counter() for _ in range(t): main() end=time.perf_counter() #print(end-start)
7
PYTHON3
a, b = [int(i) for i in input().split()] c, d = [int(i) for i in input().split()] res = [0 for i in range(10000000)] for i in range(10000): res[int(b + a*i)] = 1 for i in range(10000): if res[d + c*i] == 1: print(d+c*i) exit() print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int g, x, y; void e_gcd(int a, int b, int &g, int &x, int &y) { if (!b) { x = 1; y = 0; g = a; } else { e_gcd(b, a % b, g, y, x); y -= a / b * x; } } int main() { int a, b, c, d; scanf("%d%d%d%d", &a, &b, &c, &d); int tmp = d - b; e_gcd(a, c, g, x, y); if (tmp % g) printf("-1\n"); else { int b1 = c / g; x *= (tmp / g); x = (x % b1 + b1) % b1; while ((tmp - a * x) / c > 0) x += b1; printf("%d\n", a * x + b); } return 0; }
7
CPP
import math a, b = map(int, input().split()) c, d = map(int, input().split()) while b != d: if min(b, d) > 20000: break if b > d: d += c else: b += a print(b if b == d else -1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const double EPS = 1e-6; const double Pi = acos(-1); bool cmp(const pair<int, int> &fi, const pair<int, int> &se) { return fi.second < se.second; } long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); } long long lcm(long long a, long long b) { return a * (b / gcd(a, b)); } int dr[] = {1, 1, 0, -1, -1, -1, 0, 1}; int dc[] = {0, 1, 1, 1, 0, -1, -1, -1}; int x[1000005]; int main() { long long a, b, c, d; cin >> a >> b >> c >> d; for (int i = b; i <= 1000005; i += a) x[i] = 1; for (int i = d; i <= 1000005; i += c) if (x[i]) { cout << i << endl; return 0; } cout << -1 << endl; return 0; }
7
CPP
a, b = (int(v) for v in input().split()) c, d = (int(v) for v in input().split()) r = {b+a*i for i in range(100)} s = {d+c*i for i in range(100)} i = r.intersection(s) print(min(i) if len(i) else -1)
7
PYTHON3
a, b = map(int, list(input().split())) c, d = map(int, list(input().split())) for i in range(0, 1000): for j in range(0, 1000): if a * i + b == c * j + d: print(a * i + b) exit(0) print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; long long Inf = 1e18; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long a, b, c, d; cin >> a >> b >> c >> d; for (int i = max(b, d); i <= 1e6; i++) { if ((i - b) % a == 0 && (i - d) % c == 0) { cout << i << '\n'; return 0; } } cout << -1 << '\n'; return 0; }
7
CPP
def solve(a, b, c, d): for i in range(0, 101): j = (b + a * i - d) // c if 0 <= j and b + a * i == d + c * j: return b + a * i return -1 a, b = map(int, input().split()) c, d = map(int, input().split()) print(solve(a, b, c, d))
7
PYTHON3
#include <bits/stdc++.h> int main() { int a, b, c, d; int i; double j; scanf("%d %d %d %d", &a, &b, &c, &d); for (i = 0; i <= 100; ++i) { j = (b + a * i - d) * 1.0 / c; if (j >= 0 && j == (int)j) { printf("%d\n", b + a * i); return 0; } } puts("-1"); return 0; }
7
CPP
import re import sys from bisect import bisect, bisect_left, insort, insort_left from collections import Counter, defaultdict, deque from copy import deepcopy from decimal import Decimal from itertools import ( accumulate, combinations, combinations_with_replacement, groupby, permutations, product) from math import (acos, asin, atan, ceil, cos, degrees, factorial, gcd, hypot, log2, pi, radians, sin, sqrt, tan) from operator import itemgetter, mul from string import ascii_lowercase, ascii_uppercase, digits def inp(): return(int(input())) def inlist(): return(list(map(int, input().split()))) def instr(): s = input() return(list(s[:len(s)])) def invr(): return(map(int, input().split())) a, b = invr() c, d = invr() g = b - d if g % gcd(a, c) == 0: for y in range(101): for x in range(101): if x * c - y*a == b-d: print(b+y*a) sys.exit() else: print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; bool sortv(const vector<int>& v1, const vector<int>& v2) { return v1[0] < v2[0]; } int main() { ios_base::sync_with_stdio(false); long long int a, b, x, y; cin >> a >> b >> x >> y; for (int i = 0; i <= 500; i++) { for (int j = 0; j <= 500; j++) { if (b + (i * a) == y + (j * x)) { cout << b + (i * a); return 0; } } } cout << -1; return 0; }
7
CPP
""" *** Author--Saket Saumya *** IIITM """ import math import os import random import re from sys import stdin,stdout from collections import Counter def si(): return str(input()) def ii(): return int(input()) def mi(): return map(int, input().split()) def li(): return list(mi()) a,b=mi() c,d=mi() while(b!=d and b<1e5): if b<d: b+=a else: d+=c if b==d: print(b) else: print('-1')
7
PYTHON3
#Winners never quit, quiters never win............................................................................ from collections import deque as de import math from collections import Counter as cnt from functools import reduce from typing import MutableMapping def factors(n): return set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))) class My_stack(): def __init__(self): self.data = [] def my_push(self, x): return (self.data.append(x)) def my_pop(self): return (self.data.pop()) def my_peak(self): return (self.data[-1]) def my_contains(self, x): return (self.data.count(x)) def my_show_all(self): return (self.data) def isEmpty(self): return len(self.data)==0 arrStack = My_stack() def isPrime(n) : if (n <= 1) : return False if (n <= 3) : return True if (n % 2 == 0 or n % 3 == 0) : return False i = 5 while(i * i <= n) : if (n % i == 0 or n % (i + 2) == 0) : return False i = i + 6 return True def get_prime_factors(number): prime_factors = [] while number % 2 == 0: prime_factors.append(2) number = number / 2 for i in range(3, int(math.sqrt(number)) + 1, 2): while number % i == 0: prime_factors.append(int(i)) number = number / i if number > 2: prime_factors.append(int(number)) return prime_factors def get_frequency(list): dic={} for ele in list: if ele in dic: dic[ele] += 1 else: dic[ele] = 1 return dic def Log2(x): return (math.log10(x) / math.log10(2)); def isPowerOfTwo(n): return (math.ceil(Log2(n)) == math.floor(Log2(n))); #here we go...................... #winners never quit, quitters never win a,b=map(int,input().split()) c,d=map(int,input().split()) dic={} dic[b]=1 for i in range(1,100000): dic[b+(a*i)]=1 ch=1 for i in range(100000): if d + (c*i) in dic: print(d+(c*i)) ch=0 break if ch: print(-1)
7
PYTHON3
from sys import stdin, stdout a, b = map(int, stdin.readline().rstrip().split()) c, d = map(int, stdin.readline().rstrip().split()) match=-1 set1=set() for i in range(a+b+max([b,d])): set1.add(b+i*a) for i in range(a+b+max([b,d])): if d+i*c in set1: match=d+i*c break print(match)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long int a, b, c, d, i = 1, j = 1; cin >> a >> b >> c >> d; long long int ans1 = b; long long int ans2 = d; while (1) { if (ans1 > 10000 || ans2 > 10000) { cout << "-1"; break; } if (ans1 == ans2) { cout << ans1; break; } else { if (ans1 < ans2) { ans1 = b + (i * a); i++; } else { ans2 = d + (j * c); j++; } } } return 0; }
7
CPP
a,b=map(int,input().split()) c,d=map(int,input().split()) flag=0 if(b==d): print(b) else: for i in range(100): for j in range(100): if b+(i*a)==d+(j*c): #print(b+(i*a)) flag=1 break if(flag==1): break #else: #flag=1 # break if(flag==1): print(b+(i*a)) #break else: print(-1)
7
PYTHON3
a, b = map(int, input().split()) c, d = map(int, input().split()) for i in range(max(max(a, b), max(c, d)) + 1): if a * i + b - d >= 0 and (a * i + b - d) % c == 0: print(a * i + b) exit() print(-1)
7
PYTHON3
a, b = map(int, input().split()) c ,d = map(int, input().split()) e=set(range(b,10000,a)) f=set(range(d,10000,c)) g=e & f print(min(g) if g else -1)
7
PYTHON3
def scream_times(a,b,c,d): n = 1000 for i in range(n): for j in range(n): if(b+i*a == d+c*j): return b+i*a return -1 if __name__ == '__main__': a,b = map(int,input().split()) c,d = map(int, input().split()) print(scream_times(a,b,c,d))
7
PYTHON3
a,b = map(int,input().split()) c,d = map(int,input().split()) valid = [0]*(1000001) cnt = b while cnt <= 1000000: valid[cnt] += 1 cnt += a cnt = d while cnt <= 1000000: valid[cnt] += 1 cnt += c for i in range(1000001): if valid[i] == 2: print(i) break else: print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int inf = 1e9; int main() { int a, b, c, d; cin >> a >> b >> c >> d; int ans = inf; for (int i = 0; i <= 1000; i++) for (int j = 0; j <= 1000; j++) { if (i * a + b == j * c + d) ans = min(ans, i * a + b); } if (ans == inf) ans = -1; cout << ans << endl; }
7
CPP
from fractions import gcd import time a, b = map(int, input().split()) c, d = map(int, input().split()) gap = abs(b-d) if gap % (gcd(a, c)) != 0: print(-1) exit() while True: if b < d: r = (d - b) % a if r == 0: print(d) exit(0) b = d + (a - r) else: r = (b - d) % c if r == 0: print(b) exit(0) d = b + (c - r)
7
PYTHON3
a, b = map(int, input().split()) c, d = map(int, input().split()) if b == d: print(b) else: s = set() for i in range(0, 101): s.add(b + a * i) for i in range(0, 101): temp = d + c * i if temp in s: print(temp) exit(0) print(-1)
7
PYTHON3
import sys def diff(a, b): return abs(a - b) line1 = input() line2 = input() #line1 = '3 5' #line2 = '3 6' #line1 = '20 2' #line2 = '9 19' # #line1 = '2 1' #line2 = '16 12' interval1 = int(line1.split()[0]) offset1 = int(line1.split()[1]) interval2 = int(line2.split()[0]) offset2 = int(line2.split()[1]) diff_set = set() if offset1 <= offset2: scream1 = offset1 scream2 = offset2 int1 = interval1 int2 = interval2 else: scream1 = offset2 scream2 = offset1 int1 = interval2 int2 = interval1 while scream1 != scream2: d = diff(scream1, scream2) if d in diff_set: print(-1) sys.exit(0) else: diff_set.add(d) while scream2 > scream1: scream1 += int1 while scream1 > scream2: scream2 += int2 print(scream1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; map<long long int, bool> mp1, mp2; int main() { long long int n, i, b, a, c, d, sum1 = 0, sum2 = 0; cin >> a >> b; cin >> c >> d; sum1 = b, sum2 = d; mp1[b] = true; mp2[d] = true; for (;;) { if (sum1 > 10e5) { break; } sum1 += a; mp1[sum1] = true; } for (;;) { if (mp1[sum2] == true && mp2[sum2] == true) { cout << sum2 << endl; return 0; } if (sum2 > 10e5) { break; } sum2 += c; mp2[sum2] = true; } cout << "-1" << endl; return 0; }
7
CPP
ab = list(map(int, input().split())) a = ab[0] b = ab[1] cd = list(map(int, input().split())) c = cd[0] d = cd[1] num_list = [] if b == d: print(b) elif a > c: for i in range(max(c, d // a + 1)): num_list.append(a * i + b) for i in num_list: if (i - d) % c == 0 and i - d >= 0: print(i) break if num_list.index(i) == len(num_list) - 1: print(-1) break elif a < c: for i in range(max(a, b // c + 1)): num_list.append(c * i + d) for i in num_list: if (i - b) % a == 0 and i - b >= 0: print(i) break if num_list.index(i) == len(num_list) - 1: print(-1) break elif a == c: if (max(b, d) - min(b, d)) % a == 0: print(max(b, d)) else: print(-1)
7
PYTHON3
# b + x * a = d + y * c # x * a - y * c = d - b def main(): a, b = map(int, input().split()) c, d = map(int, input().split()) s1 = set([b + t * a for t in range(200)]) s2 = set([d + t * c for t in range(200)]) ans = float('inf') for x in s1: if x in s2: ans = min(ans, x) if ans == float('inf'): print(-1) else: print(ans) main()
7
PYTHON3
# Description of the problem can be found at http://codeforces.com/contest/787/problem/0 a, b = map(int, input().split()) c, d = map(int, input().split()) lcm = a * c for i in range(10000): t1 = b + i * a x2 = (t1 - d) // c if t1 == d + x2*c and x2 >= 0: print(t1) quit() print("-1")
7
PYTHON3
a, b = map(int, input().split()) c, d = map(int, input().split()) res = -1 k = 0 while (k < a or (d + (k - 1) * c - b) // a < 0) and res == -1: if (d + k * c - b) % a == 0 and (d + k * c - b) // a >= 0: res = d + k * c k += 1 print(res)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long i, a, b, c, d, mn, mx; cin >> a >> b >> c >> d; mn = min(b, d); b -= mn; d -= mn; if (d > b) { for (i = 0; i < 100; i++) { if (d % a == 0) { cout << d + mn; return 0; } d += c; } } else if (d < b) { for (i = 0; i < 100; i++) { if (b % c == 0) { cout << b + mn; return 0; } b += a; } } else if (d == b) { cout << d + mn; return 0; } cout << "-1"; return 0; }
7
CPP
ab = list(map(int, input().split())) a = ab[0] b = ab[1] cd = list(map(int, input().split())) c = cd[0] d = cd[1] num_list = [] if b == d: print(b) elif a >= c: for i in range(max(c, d // a + 1)): num_list.append(a * i + b) for i in num_list: if (i - d) % c == 0 and i - d >= 0: print(i) break if num_list.index(i) == len(num_list) - 1: print(-1) break elif a < c: for i in range(max(a, b // c + 1)): num_list.append(c * i + d) for i in num_list: if (i - b) % a == 0 and i - b >= 0: print(i) break if num_list.index(i) == len(num_list) - 1: print(-1) break
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long a, b, c, d; cin >> a >> b >> c >> d; for (long long i = 0; i <= 1000000; i++) { long long pos = b + i * a; if (pos >= d && ((pos - d) % c == 0)) { cout << pos << endl; return 0; } } cout << -1 << endl; }
7
CPP
import sys import collections from collections import Counter import itertools import math import timeit #input = sys.stdin.readline ######################### # imgur.com/Pkt7iIf.png # ######################### def sieve(n): if n < 2: return list() prime = [True for _ in range(n + 1)] p = 3 while p * p <= n: if prime[p]: for i in range(p * 2, n + 1, p): prime[i] = False p += 2 r = [2] for p in range(3, n + 1, 2): if prime[p]: r.append(p) return r def divs(n, start=1): divisors = [] for i in range(start, int(math.sqrt(n) + 1)): if n % i == 0: if n / i == i: divisors.append(i) else: divisors.extend([i, n // i]) return divisors def divn(n, primes): divs_number = 1 for i in primes: if n == 1: return divs_number t = 1 while n % i == 0: t += 1 n //= i divs_number *= t def flin(d, x, default = -1): left = right = -1 for i in range(len(d)): if d[i] == x: if left == -1: left = i right = i if left == -1: return (default, default) else: return (left, right) def ceil(n, k): return n // k + (n % k != 0) def ii(): return int(input()) def mi(): return map(int, input().split()) def li(): return list(map(int, input().split())) def lcm(a, b): return abs(a * b) // math.gcd(a, b) def prr(a, sep=' '): print(sep.join(map(str, a))) def dd(): return collections.defaultdict(int) def ddl(): return collections.defaultdict(list) a, b = mi() c, d = mi() for i in range(101): for j in range(101): if b + i*a == d + j*c: exit(print(b + i*a)) print(-1)
7
PYTHON3
a,b=map(int,input().split()) c,d=map(int,input().split()) for i in range(10**5+1): x=b+(a*i) if x>=d and (x-d)%c==0:print(x);exit() print(-1)
7
PYTHON3
def gcdex(a, b): i, j, k, l = 1, 0, 0, 1 while b > 0: a, b, i, j, k, l = b, a % b, k, l, i - (a // b) * k, j - (a // b) * l return a, i, j a1, b1 = map(int, input().split()) c1, d1 = map(int, input().split()) a = a1 b = -c1 c = d1 - b1 d, x, y = gcdex(abs(a), abs(b)) #print(d, x, y) if c % d == 0: a //= d b //= d c //= d x *= c y *= c x %= b y = (c - a * x) // b #print('x', x, 'y', y) #print(x * a1 + b1, c1 * y + d1) while x < 0 or y < 0 or int(y) != y: x += 1 #print('1)', x * a1 + b1, c1 * y + d1) y = (a1 * x + b1 - d1) / c1 #print('x', x, 'y', y) #print('2)', x * a1 + b1, c1 * y + d1) print(x * a1 + b1) else: print(-1)
7
PYTHON3
import sys input = sys.stdin.readline a, b = map(int, input().strip().split()) c, d = map(int, input().strip().split()) # line1 => y = ax + b # line2 => y = cx + d arr1 = [b + a*i for i in range(100)] arr2 = set([d + c*i for i in range(100)]) for ele in arr1: if ele in arr2: exit(print(ele)) print(-1)
7
PYTHON3
def sol(): for i in range(100): for j in range(100): if a*i + b == c*j + d: print(a*i + b) return print(-1) return a, b = map(int, input().split()) c, d = map(int, input().split()) sol()
7
PYTHON3
a,b = map(int, input().split()) c,d = map(int, input().split()) flag = False for i in range(500): for j in range(500): if b + a*i == d + c*j: flag = True print(b+a*i) if flag: break #break vòng này nếu đã True if flag: break #break vòng này nếu False if not flag: print(-1)
7
PYTHON3
def gcd(a, b): if b == 0: return a return gcd(b, a % b) a, b = [int(i) for i in input().split()] c, d = [int(i) for i in input().split()] g = gcd(a, c) if g != 1 and (d - b) % gcd(a, c) != 0: print (-1) exit() s1 = b s2 = d if s1 == s2: print(s1) exit() while True: while s2 < s1: s2 += c if s2 == s1: print(s1) exit() s1 += a
7
PYTHON3
a, b = list(map(int, input().split())) c, d = list(map(int, input().split())) yes = True for i in range(1, 100): if a % i == c % i and c % i == 0: if d % i != b % i: yes = False if not yes: print(-1) else: s = set() for i in range(1000): s.add(b) b += a for i in range(1000): if d in s: print(d) break d += c
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 200005; int s[N]; bool mp[N]; int main() { ios::sync_with_stdio(0); int a, b, c, d; while (cin >> a >> b >> c >> d) { memset(mp, 0, sizeof(mp)); int f = -1; for (int i = 0; i < (2000); i++) { mp[b] = 1; b += a; } for (int i = 0; i < (2000); i++) { if (mp[d]) { f = d; break; } d += c; } cout << f << endl; } return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; const long long N = 2e5 + 5; const long long INF = 1e9 + 5; vector<long long> v; map<long long, long long> mp; void solve() { long long a, b, c, d; cin >> a >> b >> c >> d; long long cnt = 0; long long tmpb = b, tmpd = d; for (long long i = 0; i <= 1e5 + 5; i++) { tmpb = b + cnt * a; tmpd = d + cnt * c; mp[tmpb]++; mp[tmpd]++; cnt++; } for (auto x : mp) { if (x.second >= 2) { cout << x.first; return; } } cout << "-1\n"; } int32_t main() { long long t; t = 1; while (t--) { solve(); } }
7
CPP
a,b=map(int,input().split()) c,d=map(int,input().split()) if b==d: print(b) else: if b<d: b+=((d-b)//a)*a for i in range(200): if (b+i*a-d)%c==0: print(b+i*a) break else: print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const double PI = acos(-1); const double eps = 1e-9; const int inf = 2000000000; int MOD1 = 1000000007; int MOD2 = 1000000009; inline bool checkBit(long long int n, long long int i) { return n & (1LL << i); } inline long long int setBit(long long int n, long long int i) { return n | (1LL << i); ; } inline long long int resetBit(long long int n, long long int i) { return n & (~(1LL << i)); } int dx[] = {0, 0, +1, -1}; int dy[] = {+1, -1, 0, 0}; inline bool EQ(double a, double b) { return fabs(a - b) < 1e-9; } inline bool isLeapYear(long long int year) { return (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0); } inline void normal(long long int &a) { a %= 1000000007; (a < 0) && (a += 1000000007); } inline long long int modMul(long long int a, long long int b) { a %= 1000000007, b %= 1000000007; normal(a), normal(b); return (a * b) % 1000000007; } inline long long int modAdd(long long int a, long long int b) { a %= 1000000007, b %= 1000000007; normal(a), normal(b); return (a + b) % 1000000007; } inline long long int modSub(long long int a, long long int b) { a %= 1000000007, b %= 1000000007; normal(a), normal(b); a -= b; normal(a); return a; } inline long long int modPow(long long int b, long long int p) { long long int r = 1LL; while (p) { if (p & 1) r = modMul(r, b); b = modMul(b, b); p >>= 1LL; } return r; } inline long long int modDiv(long long int a, long long int b) { return modMul(a, modPow(b, 1000000007 - 2)); } bool comp(const pair<int, int> &p1, const pair<int, int> &p2) { return p1.second < p2.second; } long long int converter(string a) { long long int i, mul = 1, r, t, ans = 0LL; if (a.length() == 0) return 0; for (i = a.length() - 1; i >= 0; i--) { t = a[i] - '0'; r = t % 10; ans += (mul * r); mul = mul * 10; } return ans; } bool vis[1112346]; int main() { long long int a, b; long long int c, d, i; cin >> a >> b; cin >> c >> d; for (i = 0; i <= 11000; ++i) { vis[(i * a) + b] = true; } for (i = 0; i <= 11000; ++i) { if (vis[(i * c) + d] == true) { cout << (i * c) + d << '\n'; return 0; } } cout << -1 << '\n'; return 0; }
7
CPP
from math import floor a, b = map(int, input().split()) c, d = map(int, input().split()) found = False for i in range(105): B = b + i * a j = (B - d) / c if j >= 0 and floor(j) == j: print(b + i * a) found = True break if not found: print(-1)
7
PYTHON3
def main(): a, b = [int(x) for x in input().split()] c, d = [int(x) for x in input().split()] rick = b morty = a for i in range(100): for j in range(100): if (b+i*a)==(d+j*c): print(b+i*a) return print(-1) return main()
7
PYTHON3
rick = [bool(0)] * 100001 morty = [bool(0)] * 100001 a, b = input().split(' ') a = int(a) b = int(b) c, d = input().split(' ') c = int(c) d = int(d) i = int(1) krick = -1 rick_krick = b morty_krick = d while rick_krick <= 10000: rick[rick_krick] = 1 rick_krick += a while morty_krick <= 10000: morty[morty_krick] = 1 morty_krick += c while krick == -1 and i <= 10000: if morty[i] == 1 and rick[i] == 1: krick = i i += 1 print(krick)
7
PYTHON3
def input_ints(): return list(map(int, input().split())) def main(): a, b = input_ints() c, d = input_ints() for t in range(10 ** 6): if t >= b and t >= d and (t - b) % a == 0 and (t - d) % c == 0: print(t) return print(-1) if __name__ == '__main__': main()
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int inf = 1e7; int a, b, c, d; int main() { cin >> a >> b >> c >> d; for (int i = 0; i <= inf; i++) { if (d - b + c * i >= 0 && (d - b + c * i) % a == 0) { cout << d + i * c; return 0; } } cout << -1; return 0; }
7
CPP
a, b = map(int, input().split()) c, d = map(int, input().split()) s1 = set() s2 = set() f = False b -= a d -= c for i in range(10 ** 4): b += a s1.add(b) d += c s2.add(d) if (b in s2): print(b) f = True break if (d in s1): print(d) f = True break if not f: print(-1)
7
PYTHON3
a, b = map(int, input().split()) c, d = map(int, input().split()) ans = None for i in range(b, 100**2, a): if i in range(d, 100**2, c): ans = i break if ans == None: ans = -1 print(ans)
7
PYTHON3
a, b = map(int, input().split()) c, d = map(int, input().split()) rik = [b + x*a for x in range(500)] mor = [d + x*c for x in range(500)] for r in rik: if r in mor: print(r) break else: print(-1)
7
PYTHON3
r = lambda: map(int,input().split()) a,b = r() c,d = r() # a + 2*b common = set(range(b,100**2,a)) & set(range(d,100**2,c)) print (min(common) if common else -1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c, d, i, j; cin >> a >> b >> c >> d; int f = 0; for (i = 0; i <= 100; i++) { for (j = 0; j <= 100; j++) { if (a * i + b == c * j + d) { f = 1; cout << a * i + b << endl; break; } } if (f == 1) break; } if (f == 0) cout << -1 << endl; }
7
CPP
#include <bits/stdc++.h> using namespace std; int a, b, c, d; int main() { while (~scanf("%d%d%d%d", &a, &b, &c, &d)) { int ans = -1; for (int i = 0; i < 10000; i++) { int x = d - b; int y = a * i - x; if (y >= 0 && y % c == 0) { ans = a * i + b; break; } } printf("%d\n", ans); } return 0; }
7
CPP
a=list(map(int, input().split())) b=list(map(int, input().split())) p=0 for i in range(1000): for j in range(1000): if a[1]+i*a[0]==b[1]+j*b[0]: count=a[1]+i*a[0] p=1 break if p==1: break if p==1: print(count) else: print(-1)
7
PYTHON3
a, b = map(int,input().split()) c, d = map(int,input().split()) x = d - b m = -1 n = 0 if x%a == 0: while True: m = m + 1 n = (x+m*c)/a if n < 0: continue if (x+m*c)%a == 0: print (d+m*c) break elif x%a != 0 and c%a == 0: print(-1) else: while m <= a: m = m + 1 if (x%a + (c%a)*m)%a == 0: print (d+m*c) exit() print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int MAXN = 1e3 + 7; const int INF = 1e9 + 7; int n; int main() { int a, b, c, d; scanf("%d%d%d%d", &a, &b, &c, &d); int flag = INF; for (int i = 0; i <= 1000; i++) { for (int j = 0; j <= 1000; j++) if (b + i * a == d + j * c) { flag = min(flag, b + i * a); break; } } if (flag == INF) flag = -1; printf("%d\n", flag); }
7
CPP
#include <bits/stdc++.h> using namespace std; int a, b, c, d; int ans; int main() { scanf("%d%d%d%d", &a, &b, &c, &d); ans = -1; for (int i = 0; i <= 999; ++i) for (int j = 0; j <= 999; ++j) if (b + a * i == d + c * j) ans = min(ans == -1 ? 1000000000 : ans, b + a * i); printf("%d\n", ans); return 0; }
7
CPP
#include <bits/stdc++.h> int main() { int a, b, c, d, x, i, z[105]; scanf("%d%d%d%d", &a, &b, &c, &d); for (i = 0; i < 105; i++) z[i] = 0; for (x = 0, i = 0; b != d; i++) { if (a * i + b - d >= 0) { if ((a * i + b - d) % c == 0) break; else if (z[(a * i + b - d) % c] == 1) { x = 1; break; } z[(a * i + b - d) % c] = 1; } } if (x == 1) printf("-1\n"); else printf("%d\n", a * i + b); return 0; }
7
CPP
a,b=map(int,input().split()) c,d=map(int,input().split()) for i in range(100000): if (b+i*a-d)%c==0 and b+i*a-d>=0: print(b+i*a) break else: print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c, d, i, j, flag; while (~scanf("%d%d%d%d", &a, &b, &c, &d)) { flag = 0; for (i = 0; i <= 10000; i++) { for (j = 0; j <= 10000; j++) { if ((b + a * i) == (d + c * j)) { flag = 1; break; } if ((b + a * i) < (d + c * j)) { break; } } if (flag == 1) { break; } } if (flag) { printf("%d\n", b + a * i); } else { printf("-1\n"); } } return 0; }
7
CPP
def sum_(a_, d_): return a_ + n * d_ a, b = map(int, input().split(' ')) c, d = map(int, input().split(' ')) lim = a * c + b + d n = 0 sli = [sum_(b, a)] while sli[n] <= lim: n += 1 sli.append(sum_(b, a)) n = 0 slj = [sum_(d, c)] while slj[n] <= lim: n += 1 slj.append(sum_(d, c)) r = -1 for i in sli: for j in slj: if i == j: r = j break if i == r: break print(r)
7
PYTHON3
import sys [a, b] = [int(x) for x in input().split(" ")] [c, d] = [int(x) for x in input().split(" ")] # aX + b == cY + d maximum = max(a, b, c, d) for i in range(maximum + 1): y = (a * i + b - d) / c x = (c * y + d - b) / a answer = (a * i + b) if (x).is_integer() and (y).is_integer() and answer >= max(b, d): print(answer) sys.exit() print(-1)
7
PYTHON3
import sys a, b = map(int, input().split()) c, d = map(int, input().split()) for i in range(max(b,d),100000): if (i-b) % a == 0 and (i-d) % c == 0: print(i) sys.exit() print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int b, a, d, c; cin >> a >> b >> c >> d; int k = 0; while (b != d) { if (d > b) { b += a; } else { d += c; } k++; if (k == 100005) { cout << "-1"; return 0; } } cout << b; return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; using ll = long long; int main() { ios::sync_with_stdio(0), cin.tie(0); int a, b, c, d; cin >> a >> b >> c >> d; for (int i = max(b, d); i <= 1e5; ++i) if ((i - b) % a == 0 && (i - d) % c == 0) return cout << i, 0; cout << -1; return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; int gcd(int a, int b) { while (a != b) if (a > b) a -= b; else b -= a; return a; } int main() { int a, b, c, d, i = 1, j = 1, k; cin >> a >> b >> c >> d; if (abs(d - b) % gcd(a, c)) cout << -1; else { while (b != d) { if (b < d) b += a; else d += c; } cout << b; } }
7
CPP
a,b=map(int,input().split()) c,d=map(int,input().split()) t=[] for n1 in range(1,101): for n2 in range(1,101): if(b+(n1-1)*a==d+(n2-1)*c): t.append(b+(n1-1)*a) if len(t)!=0: print(min(t)) else: print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c, d, i, j = -1, x, y; cin >> a >> b >> c >> d; int t[100], s[100]; for (i = 0; i < 100; i++) { j++; x = b + a * i; t[i] = {x}; y = d + c * j; s[i] = {y}; } for (i = 0; i < 100; i++) { for (j = 0; j < 100; j++) { if (t[i] == s[j]) { cout << t[i]; return 0; } } } cout << "-1"; return 0; }
7
CPP
ans=[] a,b=map(int,input().split()) c,d=map(int,input().split()) l=[b,b+a] ll=[d,d+c] for i in range(100): l+=[b+i*a] for i in range(100): ll+=[d+i*c] for i in l: if i in ll: ans+=[i] if len(ans)==0: print(-1) else: print(ans[0])
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int p[100010], q[100010]; int main() { int a, b, c, d; cin >> a >> b >> c >> d; map<int, int> mp; for (int i = 0; i <= 10000; i++) { p[i] = b + a * i; q[i] = d + c * i; mp[q[i]] = 1; } for (int i = 0; i <= 10000; i++) { if (mp[p[i]]) { cout << p[i] << endl; return 0; } } cout << "-1" << endl; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); int a, b, c, d; cin >> a >> b >> c >> d; int flag = 1; for (int i = 0; i < 100; i++) { int lhs = a * i + b; int j = (lhs - d) / c; if (j < 0) continue; int rhs = c * j + d; if (lhs == rhs) { flag = 0; cout << lhs << endl; break; } } if (flag) cout << -1 << endl; return 0; }
7
CPP
a,b = map(int, input().split()) c,d = map(int, input().split()) for i in range(1000 * 1000): if (d - b + i * c) % a == 0 and (d - b + i * c) > -1: print(d + i * c) exit(0) print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; #pragma comment(linker, "/STACK:102400000,102400000") const int maxn = 1000000 + 5; bool vis[maxn]; int main() { int a, b, c, d; cin >> a >> b >> c >> d; vis[b] = true; for (int i = 1; b <= maxn - 5; i++) { vis[b] = true; b += a; } bool flag = false; for (int i = 1; d <= maxn - 5; i++) { if (vis[d]) { flag = true; break; } d += c; } if (flag) printf("%d\n", d); else printf("-1\n"); return 0; }
7
CPP
a,b=map(int,input().split()) s=0 c,d=map(int,input().split()) flag=0 while(d!=b): if(s==100000): print(-1) b=d flag=1 if(d<b): d+=max(c*((b-d)//c),c) else: b+=max(a*((d-b)//a),a) s+=1 if(flag==0): print(b)
7
PYTHON3
import math def gcdex(a, b): if b == 0: return a, 1, 0 else: d, x1, y1 = gcdex(b, a % b) return d, y1, x1 - (a // b) * y1 n1, n2 = map(int, input().split()) n3, n4 = map(int, input().split()) a = n1 b = -n3 c = n4 - n2 d, x0, y0 = gcdex(abs(a), abs(b)) if c % d != 0: print(-1) else: x0 *= c // d y0 *= c // d if (a < 0): x0 *= -1 if (b < 0): y0 *= -1 if b // d > 0: while x0 < 0 or y0 < 0: x0 += b//d y0 -= a//d if b // d < 0: while x0 < 0 or y0 < 0: x0 -= b//d y0 += a//d if b // d > 0: while x0 >= 0 and y0 >= 0: x0 -= b//d y0 += a//d x0 += b//d y0 -= a//d if b // d < 0: while x0 >= 0 and y0 >= 0: x0 += b//d y0 -= a//d x0 -= b//d y0 += a//d print(n2 + x0 * n1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; bool x[10001000]; int main() { int a, b, c, d; cin >> a >> b >> c >> d; for (int i = 0; i < 100000; i++) { x[b + i * a] = 1; } bool ok = false; for (int i = 0; i < 100000; i++) { int t = d + i * c; if (x[t]) { ok = true; cout << t << endl; break; } } if (!ok) cout << -1 << endl; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { short a, b, c, d; cin >> a >> b >> c >> d; short n1 = b, n2 = d; do { if (n2 > n1) do { n1 += a; if (n1 < 0) n1 = -1; } while (n1 > 0 && n2 > n1); if (n1 > n2) do { n2 += c; if (n2 < 0) n1 = -1; } while (n1 > 0 && n1 > n2); } while (n1 > 0 && n1 != n2); cout << n1; }
7
CPP
def gcd(a, b): if b == 0: return a return gcd(b, a%b) from sys import stdin a, b = map(int, stdin.readline().split()) c, d = map(int, stdin.readline().split()) const = b - d + c - a # m*c + n*(-a) = const # Linear Diophantine equation gives the below if condition. if const%gcd(a, c) == 0: for m in range(1, 10**7): if m*c>=const: if (m*c - const)/a == (m*c - const)//a: print(b + ((m*c - const)//a - 1)*a) break else: print(-1)
7
PYTHON3
l=input().split() s=input().split() a=int(l[0]) b=int(l[1]) c=int(s[0]) d=int(s[1]) t=[] p=[] f=1 i=0 while(i<1000): t.append(b+i*a) p.append(d+i*c) if(b+i*a in p): print(b+i*a) f=0 break if(d+i*c in t): print(d+i*c) f=0 break i+=1 if(f): print("-1")
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int INF = 0x3f3f3f3f; int main() { ios::sync_with_stdio(0); int a, b, c, d; scanf("%d %d", &a, &b); scanf("%d %d", &c, &d); for (int i = 0; i < 10000000; i++) { int k = b + a * i; if (k - d < 0) continue; if ((k - d) % c == 0) { printf("%d", k); return 0; } } printf("-1"); return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c, d; int i; double j; cin >> a >> b >> c >> d; for (i = 0; i <= 100; ++i) { j = (b + a * i - d) * 1.0 / c; if (j >= 0 && j == (int)j) { cout << (b + a * i); return 0; } } cout << -1 << endl; return 0; }
7
CPP
#include <bits/stdc++.h> #pragma comment(linker, "/STACK:256000000") using namespace std; const int INF = 1000001000; const long long INFLL = INF * 1LL * INF; const int mod = 1000 * 1000 * 1000 + 7; const int mod9 = 1000 * 1000 * 1000 + 9; const int modr = 99990001; const long double PI = 3.1415926535897932385; template <class T> void zero(T val, T& first) { first = val; } template <class T, class... Targs> void zero(T val, T& first, Targs&... Fargs) { first = val; zero(val, Fargs...); } template <class T, class T2> std::istream& operator>>(std::istream& is, pair<T, T2>& p) { return is >> p.first >> p.second; } template <class T> std::istream& readN(T& first, int n, int st = 0) { for (int i = st, iend = (st + n - 1); i <= iend; i++) cin >> first[i]; return cin; } template <class T> std::istream& readS(set<T>& first, int n) { T second = *first.rbegin(); for (int i = 0, iend = (n - 1); i <= iend; i++) { cin >> second; first.insert(second); } return cin; } template <class T> std::istream& read(T& first) { return cin >> first; } template <class T, class... Targs> std::istream& read(T& first, Targs&... Fargs) { return read(first), read(Fargs...); } template <class T, class T2> std::ostream& operator<<(std::ostream& os, pair<T, T2> p) { return os << p.first << " " << p.second; } template <class T> std::ostream& operator<<(std::ostream& os, vector<T> v) { bool f = true; for (auto second : v) { if (!f) os << ' '; os << second; f = false; } return os; } template <class T> std::ostream& operator<<(std::ostream& os, set<T> v) { bool f = true; for (auto second : v) { if (!f) os << ' '; os << second; f = false; } return os; } template <class T> std::ostream& operator<<(std::ostream& os, multiset<T> v) { bool f = true; for (auto second : v) { if (!f) os << ' '; os << second; f = false; } return os; } template <class T, class T2> std::ostream& operator<<(std::ostream& os, map<T, T2> v) { bool f = true; for (pair<T, T2> second : v) { if (!f) os << ' '; os << second.first << "=>" << second.second; f = false; } return os; } template <class T> std::ostream& outV(T first, char del = ' ') { bool f = true; for (auto second : first) { if (!f) cout << del; cout << second; f = false; } return cout; } template <class T> std::ostream& outN(T first, int n = -1, int st = 0) { for (int i = st, iend = (n == -1 ? (int)first.size() - 1 : st + n - 1); i <= iend; i++) { cout << first[i]; if (i < iend) cout << ' '; } return cout; } template <class T> std::ostream& outAN(T first, int n = -1, int st = 0) { for (int i = st, iend = (n - 1); i <= iend; i++) { cout << first[i]; if (i < iend) cout << ' '; } return cout; } template <class T> std::ostream& outA2(T first, int n, int m) { for (int i = 0, iend = (n - 1); i <= iend; i++) { for (int j = 0, jend = (m - 1); j <= jend; j++) cout << first[i][j] << (j == m - 1 ? '\n' : ' '); } return cout; } template <class T> std::ostream& out(T first) { return cout << first; } template <class T, class... Targs> std::ostream& out(T first, Targs... Fargs) { return out(first) << " ", out(Fargs...); } template <typename T> void srt(T& a, int st, int fn, bool isArr) { sort(a + st, a + fn + 1); } template <class T> void srt(T& a, int st = 0, int fn = 0) { sort(a.begin() + st, fn ? a.begin() + fn + 1 : a.end()); } template <typename T> T rev_num(T a) { T r = 0; for (; a; a /= 10) r = r * 10 + a % 10; return r; } template <typename T> void rev(T& a, int st, int fn, bool isArr) { reverse(a + st, a + fn + 1); } template <class T> void rev(T& a, int st = 0, int fn = 0) { reverse(a.begin() + st, fn ? a.begin() + fn + 1 : a.end()); } long long sqr(long long a) { return a * a; }; long long sqr(int a) { return a * 1LL * a; }; long double sqr(long double a) { return a * a; }; long double dist(pair<long long, long long> first, pair<long long, long long> second) { return sqrt(sqr(first.first - second.first) + sqr(first.second - second.second)); } long long phi(int n) { int res = n; for (long long i = 2; i * i <= n; i++) if (n % i == 0) { while (n % i == 0) n /= i; res -= res / i; } if (n > 1) res -= res / n; return res; } long long bpm(long long a, long long n = -2, long long m = mod) { n = n < 0 ? n + m : n; long long r = 1; while (n) { if (n & 1) r = (r * a) % m; a = (a * a) % m; n >>= 1; } return r; } unsigned long long gcd(unsigned long long a, unsigned long long b) { while (b) { a %= b; swap(a, b); } return a; } vector<int> ero_p, ero_l; void ero(int n) { ero_l.resize(n + 1); ero_l[0] = -1; for (int i = 2, iend = (n); i <= iend; i++) if (!ero_l[i]) { ero_p.push_back(i); ero_l[i] = i; for (long long j = i * 1LL * i; j <= n; j += i) { ero_l[j] = i; } } } long long gcd_cb(long long a, long long b, long long& first, long long& second) { if (!b) { first = 1; second = 0; return a; } long long x1, y1, g; g = gcd_cb(b, a % b, x1, y1); first = y1; second = x1 - a / b * y1; return g; } vector<long long> fact; void fact_prec(int n = 20) { fact.resize(n + 1); fact[0] = 1; for (int i = 1, iend = (n); i <= iend; i++) { fact[i] = fact[i - 1] * i; } } vector<long double> factd; void fact_precd(int n = 146) { factd.resize(n + 1); factd[0] = 1; for (int i = 1, iend = (n); i <= iend; i++) { factd[i] = factd[i - 1] * i; } } string str(long long a) { string r = ""; for (; a; a /= 10) r += a % 10 + '0'; rev(r); return r; } template <class T> int bitc(T first) { int r = 0; for (T d = first; d >= 0; d >>= 1) r += d & 1; return r; } const int N = 7000006; int main() { long long a, b, c, d; read(a, b, c, d); long long ans = -1; for (int i = 0, iend = (100005 - 1); i <= iend; i++) { long long time = a * i + b; if (time >= d && (time - d) % c == 0) { ans = time; break; } } out(ans) << "\n"; return 0; }
7
CPP
#The Monster a, b = map(int, input().split()) c, d = map(int, input().split()) same_time = 0 coeff = 0 count = 0 if (a % 2 == 0 and b % 2 != 0) and c % 2 == 0 and d % 2 == 0: print("-1") elif (a % 2 == 0 and b % 2 == 0) and c % 2 == 0 and d % 2 != 0: print("-1") elif b == d: print(b) else: if b > d: g = a h = b i = c j = d else: g = c h = d i = a j = b # Think of each scream as just an addition to the last??? # ab a+b, b+a+a, b+a+a+a.... new_gh = h new_ij = j while True: # test until one one is larger than the other, then flip if new_gh / new_ij == 1: print(new_gh) break if new_gh > new_ij: new_ij += i if new_gh < new_ij: new_gh += g count += 1 if count == 10000: print(-1) break
7
PYTHON3
def gcd(a,b): if a < 0: a = -a if b < 0: b = -b while b != 0: r = a % b a,b = b, r return a a,b = map(int, input().split()) c, d = map(int, input().split()) if (d - b) % gcd(a, c) != 0: print(-1) else: i = 0 while True: j = (b + i*a-d)//c if j >= 0 and (b + i*a == d+j*c): print(b + i*a) break i+=1
7
PYTHON3
def main(): a, b = map(int, input().split()) c, d = map(int, input().split()) for i in range(100000): if i - b >= 0 and (i - b) % a == 0: if i - d >= 0 and (i - d) % c == 0: print(i) return print(-1) main()
7
PYTHON3
a,b = map(int,input().split()) c,d = map(int,input().split()) for i in range(0,1000): for j in range(0,1000): if b + a*i == d + c*j: print(b + a*i) exit(0) print(-1)
7
PYTHON3
import sys a, b = map(int, input().split()) c, d = map(int, input().split()) s = set() for i in range(1001): s.add( b + i * a) for i in range(1000): num = d + c * i if num in s: print(num) sys.exit() print(-1)
7
PYTHON3
inp = input().split() a = int(inp[0]) b = int(inp[1]) inp = input().split() c = int(inp[0]) d = int(inp[1]) for x in range(101): for y in range(101): if (a*x+b) == (c*y+d): print(a*x+b) exit(0) print(-1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long int a, b, c, d; while (cin >> a >> b >> c >> d) { map<long long int, long long int> p; for (long long int i = 0; i <= 100; i++) { long long int x = b + a * i; p[x] = 1; } bool f = true; for (long long int i = 0; i <= 100; i++) { long long int x = d + c * i; if (p[x]) { cout << x << endl; f = false; break; } } if (f) cout << "-1" << endl; } }
7
CPP
a,b = map(int,input().split()) c,d = map(int,input().split()) for i in range(100000): if(b+a*i-d)>=0 and (b+a*i-d)%c==0: print(b+a*i) break else: print(-1)
7
PYTHON3
i=1 yes=-1 y=0 a,b=map(int,input().split()) c,d=map(int,input().split()) #both Equations are in a form of straight line. #the case is if we draw one line segment prependicular on y then #definetly, the two points will pass through that line and Morty and Rick must be equal. #i*a+b=j*c+d, if(b==d): print(d) else: for j in range(100): i=(j*c+d-b)/a if (i-int(i)==0 and i>=0): yes=i if(yes!=-1): break if (yes==-1): print(-1) else: y=yes*a+b print(int(y))
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c, d; cin >> a >> b >> c >> d; int i = 0, j = 0; while (b != d && i <= 100 && j <= 100) { if (b > d) { d += c; j++; } else { b += a; i++; } } if (i <= 100 && j <= 100) cout << d << endl; else cout << -1 << endl; return 0; }
7
CPP
a,b = map(int,input().split(' ')) c,d = map(int,input().split(' ')) for x in range(0,101): f = False for y in range(0,101): if (a*x+b) - (c*y+d) == 0: print(a*x+b) f = True break if f: break; if f == False: print(-1)
7
PYTHON3