Create README.md

README.md

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+Usage:
+
+```python
+import torch
+from transformers import AutoTokenizer, AutoModelForCausalLM
+
+question_template = "# Question\n\n{question}\n\n# Solution\n\n"
+
+model_name = "ScalableMath/llemma-7b-sft-metamath-level-1to3-hf"
+model = AutoModelForCausalLM.from_pretrained(model_name, torch_dtype=torch.bfloat16, device_map="auto")
+
+tokenizer = AutoTokenizer.from_pretrained("EleutherAI/llemma_7b")
+
+question = "Convert the point $(0,3)$ in rectangular coordinates to polar coordinates.  Enter your answer in the form $(r,\\theta),$ where $r > 0$ and $0 \\le \\theta < 2 \\pi.$"
+question = question_template.format(question=question)
+
+input_tensor = torch.tensor([tokenizer.encode(question)])
+outputs = model.generate(input_tensor.to(model.device), max_new_tokens=500)
+
+result = tokenizer.decode(outputs[0], skip_special_tokens=True)
+print(result)
+```
+
+Example result:
+
+```
+# Question
+Convert the point $(0,3)$ in rectangular coordinates to polar coordinates.  Enter your answer in the form $(r,\theta),$ where $r > 0$ and $0 \le \theta < 2 \pi.$
+
+# Solution
+To convert from rectangular coordinates to polar coordinates, we use the formulas $r = \sqrt{x^2 + y^2}$ and $\theta = \arctan\left(\frac{y}{x}\right)$.
+
+In this case, $x = 0$ and $y = 3$, so $r = \sqrt{0^2 + 3^2} = 3$ and $\theta = \arctan\left(\frac{3}{0}\right)$.
+
+Since $\frac{3}{0}$ is undefined, we can say that $\theta$ is undefined.
+However, we know that $\theta$ is an angle, and since $r > 0$, we can say that $\theta$ is any angle that satisfies $0 \le \theta < 2 \pi$.
+
+Therefore, the polar coordinates of the point $(0,3)$ are $\boxed{(3,\theta)}$, where $0 \le \theta < 2 \pi$.
+
+# Answer
+
+(3,\theta)
+```